An electron gun in CRT emits electron which moves with the speecd of 3×106 m/s it pasess through a uniform 4.0T magnetic field along the + y-axis . He velocity of each electron is at 50° to the y-axis and lies in the xy-plane.Find the magnitude and direction of force on electron?

An electron gun in CRT emits electron which moves with the speecd of 3×106 m/s it pasess through a uniform 4.0T magnetic field along the + y-axis . He velocity of each electron is at 50° to the y-axis and lies in the xy-plane.Find the magnitude and direction of force on electron?

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Question

An electron gun in CRT emits electron which moves with the speecd of 3×10⁶ m/s it pasess through a uniform 4.0T magnetic field along the + y-axis . He velocity of each electron is at 50° to the y-axis and lies in the xy-plane.Find the magnitude and direction of force on electron?

Expert Solution

Step 1

Given information:

The velocity of electrons, $v = 3 \times 10^{6} m / s$

The magnetic field, $B = 4.0 T$

The angle between the velocity vector and the magnetic field, $θ = 50 °$

We have to find the magnitude and direction of the force on the electrons.

Step by step

Solved in 4 steps

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