An electron at point A has a speed vo of 1.50 x 10 m/s. What is the magnitude and dire ion of ma netic field that will cause the electron to follow the semicircular path from A to B? (qe = -1.60 x 10-19 C, me = 9.11 x 10-31 kg)
An electron at point A has a speed vo of 1.50 x 10 m/s. What is the magnitude and dire ion of ma netic field that will cause the electron to follow the semicircular path from A to B? (qe = -1.60 x 10-19 C, me = 9.11 x 10-31 kg)
Related questions
Question
![**Transcription of Educational Content:**
Title: Determining Magnetic Field for Electron Path
An electron at point A has a speed \( v_0 \) of \( 1.50 \times 10^5 \, \text{m/s} \). What is the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B?
Given:
- Electron charge (\( q_e \)) = \( -1.60 \times 10^{-19} \, \text{C} \)
- Electron mass (\( m_e \)) = \( 9.11 \times 10^{-31} \, \text{kg} \)
Options:
- \( 8.52 \times 10^{-6} \, \text{T}, \) out of page
- \( 1.71 \times 10^{-5} \, \text{T}, \) into the page
- \( 3.41 \times 10^{-19} \, \text{T}, \) into the page
- \( 1.71 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) into the page
- \( 8.52 \times 10^{-6} \, \text{T}, \) into the page
(Note: The options specify both the magnitude of the magnetic field in Tesla (T) and its direction relative to the page.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8daeabfb-08fc-4e08-b5f3-009f3913f10d%2F918e4980-15b6-4f92-b1b3-21c53e9bd958%2F6gd0imp_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription of Educational Content:**
Title: Determining Magnetic Field for Electron Path
An electron at point A has a speed \( v_0 \) of \( 1.50 \times 10^5 \, \text{m/s} \). What is the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B?
Given:
- Electron charge (\( q_e \)) = \( -1.60 \times 10^{-19} \, \text{C} \)
- Electron mass (\( m_e \)) = \( 9.11 \times 10^{-31} \, \text{kg} \)
Options:
- \( 8.52 \times 10^{-6} \, \text{T}, \) out of page
- \( 1.71 \times 10^{-5} \, \text{T}, \) into the page
- \( 3.41 \times 10^{-19} \, \text{T}, \) into the page
- \( 1.71 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) into the page
- \( 8.52 \times 10^{-6} \, \text{T}, \) into the page
(Note: The options specify both the magnitude of the magnetic field in Tesla (T) and its direction relative to the page.)
![The image features a diagram depicting the motion of a particle under the influence of a force. The diagram includes the following elements:
1. **A Particle at Point A:**
- A blue circle labeled "A" represents a particle at the starting point.
- There is a negative sign inside the circle, indicating a negative charge or potential.
- A green horizontal arrow labeled \( v_0 \) is pointing to the left, indicating the initial velocity direction of the particle.
2. **Path of Motion:**
- A dashed blue curved line with arrows shows the trajectory of the particle. The path curves downward, suggesting the influence of gravity or another force acting in that direction.
3. **Points A and B:**
- The vertical distance between points A and B is marked as 12.0 cm. This may represent a drop or height that the particle travels downward along its path.
This diagram is likely used to illustrate a concept in physics, such as projectile motion or the behavior of a charged particle in an electric field.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F8daeabfb-08fc-4e08-b5f3-009f3913f10d%2F918e4980-15b6-4f92-b1b3-21c53e9bd958%2Fmyikmyz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:The image features a diagram depicting the motion of a particle under the influence of a force. The diagram includes the following elements:
1. **A Particle at Point A:**
- A blue circle labeled "A" represents a particle at the starting point.
- There is a negative sign inside the circle, indicating a negative charge or potential.
- A green horizontal arrow labeled \( v_0 \) is pointing to the left, indicating the initial velocity direction of the particle.
2. **Path of Motion:**
- A dashed blue curved line with arrows shows the trajectory of the particle. The path curves downward, suggesting the influence of gravity or another force acting in that direction.
3. **Points A and B:**
- The vertical distance between points A and B is marked as 12.0 cm. This may represent a drop or height that the particle travels downward along its path.
This diagram is likely used to illustrate a concept in physics, such as projectile motion or the behavior of a charged particle in an electric field.
Expert Solution
![](/static/compass_v2/shared-icons/check-mark.png)
This question has been solved!
Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.
Step by step
Solved in 3 steps
![Blurred answer](/static/compass_v2/solution-images/blurred-answer.jpg)