An electron at point A has a speed vo of 1.50 x 10 m/s. What is the magnitude and dire ion of ma netic field that will cause the electron to follow the semicircular path from A to B? (qe = -1.60 x 10-19 C, me = 9.11 x 10-31 kg)

icon
Related questions
Question
**Transcription of Educational Content:**

Title: Determining Magnetic Field for Electron Path

An electron at point A has a speed \( v_0 \) of \( 1.50 \times 10^5 \, \text{m/s} \). What is the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B? 

Given:
- Electron charge (\( q_e \)) = \( -1.60 \times 10^{-19} \, \text{C} \)
- Electron mass (\( m_e \)) = \( 9.11 \times 10^{-31} \, \text{kg} \)

Options:
- \( 8.52 \times 10^{-6} \, \text{T}, \) out of page
- \( 1.71 \times 10^{-5} \, \text{T}, \) into the page
- \( 3.41 \times 10^{-19} \, \text{T}, \) into the page
- \( 1.71 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) out of page
- \( 1.42 \times 10^{-5} \, \text{T}, \) into the page
- \( 8.52 \times 10^{-6} \, \text{T}, \) into the page

(Note: The options specify both the magnitude of the magnetic field in Tesla (T) and its direction relative to the page.)
Transcribed Image Text:**Transcription of Educational Content:** Title: Determining Magnetic Field for Electron Path An electron at point A has a speed \( v_0 \) of \( 1.50 \times 10^5 \, \text{m/s} \). What is the magnitude and direction of the magnetic field that will cause the electron to follow the semicircular path from A to B? Given: - Electron charge (\( q_e \)) = \( -1.60 \times 10^{-19} \, \text{C} \) - Electron mass (\( m_e \)) = \( 9.11 \times 10^{-31} \, \text{kg} \) Options: - \( 8.52 \times 10^{-6} \, \text{T}, \) out of page - \( 1.71 \times 10^{-5} \, \text{T}, \) into the page - \( 3.41 \times 10^{-19} \, \text{T}, \) into the page - \( 1.71 \times 10^{-5} \, \text{T}, \) out of page - \( 1.42 \times 10^{-5} \, \text{T}, \) out of page - \( 1.42 \times 10^{-5} \, \text{T}, \) into the page - \( 8.52 \times 10^{-6} \, \text{T}, \) into the page (Note: The options specify both the magnitude of the magnetic field in Tesla (T) and its direction relative to the page.)
The image features a diagram depicting the motion of a particle under the influence of a force. The diagram includes the following elements:

1. **A Particle at Point A:**
   - A blue circle labeled "A" represents a particle at the starting point.
   - There is a negative sign inside the circle, indicating a negative charge or potential.
   - A green horizontal arrow labeled \( v_0 \) is pointing to the left, indicating the initial velocity direction of the particle.

2. **Path of Motion:**
   - A dashed blue curved line with arrows shows the trajectory of the particle. The path curves downward, suggesting the influence of gravity or another force acting in that direction.

3. **Points A and B:**
   - The vertical distance between points A and B is marked as 12.0 cm. This may represent a drop or height that the particle travels downward along its path.

This diagram is likely used to illustrate a concept in physics, such as projectile motion or the behavior of a charged particle in an electric field.
Transcribed Image Text:The image features a diagram depicting the motion of a particle under the influence of a force. The diagram includes the following elements: 1. **A Particle at Point A:** - A blue circle labeled "A" represents a particle at the starting point. - There is a negative sign inside the circle, indicating a negative charge or potential. - A green horizontal arrow labeled \( v_0 \) is pointing to the left, indicating the initial velocity direction of the particle. 2. **Path of Motion:** - A dashed blue curved line with arrows shows the trajectory of the particle. The path curves downward, suggesting the influence of gravity or another force acting in that direction. 3. **Points A and B:** - The vertical distance between points A and B is marked as 12.0 cm. This may represent a drop or height that the particle travels downward along its path. This diagram is likely used to illustrate a concept in physics, such as projectile motion or the behavior of a charged particle in an electric field.
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions