An electron accelerates between the cathode and the anode. It passes through a potential difference of 2000 V. The charge on an electron is 1.6 × 10-19 C and the mass of an electron is 9.1 × 10-31 kg. a. Calculate the work done on the electron passing through a pd of 2000 V. Give your answer in joules. b. The work done on the electron becomes kinetic energy of the electron. Write down the formula for kinetic energy in terms of mass m and speed v. c. Using your answers to questions a and b, find the speed of the electron.
Situation:
An electron accelerates between the cathode and the anode. It passes through a potential difference of 2000 V.
The charge on an electron is 1.6 × 10-19 C and the mass of an electron is 9.1 × 10-31 kg.
a. Calculate the work done on the electron passing through a pd of 2000 V. Give your answer in joules.
b. The work done on the electron becomes kinetic energy of the electron. Write down the formula for kinetic energy in terms of mass m and speed v.
c. Using your answers to questions a and b, find the speed of the electron.
d. The anode is connected to the screen. State and explain what, if anything, happens to the speed of the electron as it passes from the anode to the screen.
e. In 10 seconds, 6.0 × 10^17 electrons hit the screen. Calculate:
(a) the charge hitting the screen in 10 seconds (the charge on an electron is given above)
(b) the current in the electron beam.
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