An electromagnetic wave in vacuum travels in the +x-direction with Emax = 455 V/m and a wavelength of 12.7 m. Calculate the x-component of its Poynting vector at x = 0, t = 0.13 µs. (Use c = 2.9979 × 108 m/s)
An electromagnetic wave in vacuum travels in the +x-direction with Emax = 455 V/m and a wavelength of 12.7 m. Calculate the x-component of its Poynting vector at x = 0, t = 0.13 µs. (Use c = 2.9979 × 108 m/s)
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![**Problem Description:**
An electromagnetic wave in vacuum travels in the +x-direction with \( E_{\text{max}} = 455 \, \text{V/m} \) and a wavelength of 12.7 m. Calculate the x-component of its Poynting vector at \( x = 0 \), \( t = 0.13 \, \mu \text{s} \). (Use \( c = 2.9979 \times 10^8 \, \text{m/s} \))
**Solution Explanation:**
To solve this, the x-component of the Poynting vector \( \mathbf{S} \) is given by:
\[
S_x = \frac{E \times B}{\mu_0}
\]
Where \( E \) is the electric field, \( B \) is the magnetic field, and \( \mu_0 \) is the vacuum permeability (\( \mu_0 = 4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A} \)).
The magnetic field in a vacuum can be related to the electric field as:
\[
B = \frac{E}{c}
\]
Thus, the instantaneous Poynting vector at \( x = 0 \), \( t = 0.13 \, \mu\text{s} \) can be calculated.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F71da004f-23dc-47ac-9c54-84cf84b3724a%2Fc17e0c55-c144-4fcb-9e17-65c0a32abc36%2Frufbtvh_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Description:**
An electromagnetic wave in vacuum travels in the +x-direction with \( E_{\text{max}} = 455 \, \text{V/m} \) and a wavelength of 12.7 m. Calculate the x-component of its Poynting vector at \( x = 0 \), \( t = 0.13 \, \mu \text{s} \). (Use \( c = 2.9979 \times 10^8 \, \text{m/s} \))
**Solution Explanation:**
To solve this, the x-component of the Poynting vector \( \mathbf{S} \) is given by:
\[
S_x = \frac{E \times B}{\mu_0}
\]
Where \( E \) is the electric field, \( B \) is the magnetic field, and \( \mu_0 \) is the vacuum permeability (\( \mu_0 = 4\pi \times 10^{-7} \, \text{T}\cdot\text{m/A} \)).
The magnetic field in a vacuum can be related to the electric field as:
\[
B = \frac{E}{c}
\]
Thus, the instantaneous Poynting vector at \( x = 0 \), \( t = 0.13 \, \mu\text{s} \) can be calculated.
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