An electrochemical cell is set up with the following configuration: Hg|Hg2+||Mn2+|Mn.  The solutions are, respectively, 0.1 M Hg(NO3)2 (aq) and 0.1 M Mn(NO3)2 (aq).  A voltmeter connected between the two electrodes reads -2.16 V.  a.    Write the two half-reactions for the cell as written. b.    The standard reduction potential for Mn2+ + 2e- ® Mn is E° = -1.18 V.

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A: Given that -  Zn ----> Zn2+ + 2e-  VZn0 = -0.763 V  Cu2+ + 2e- ------> Cu        VCu0 = +0.340…

Q: An electrochemical cell is set up with the following configuration: Hg|Hg2+||Mn2+|Mn.  The solutions…

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A: Dear student , since you have posted multiple parts questions we are allowed to solve only first…

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A:

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A:

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Q: An electrochemical cell is set up with the following configuration: Hg|Hg2+||Mn2+|Mn.  The solutions…

A:

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A: Since you have posted question with multiple subparts as per guidelines we can answer only three per…

Q: 6. Which of the following correctly differentiate a galvanic from an electrolytic cell? GALVANIC…

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A: Since you have posted multiple questions, the answer for first question is given below. Kindly…

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A:

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A: Hence option A is correct that is -311kJ/mol

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A:

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A: The answer is discussed below, Oxidation occurs at the anode and reduction occurs at the cathode.

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A:

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Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.