An electrochemical cell is based on these two half-reactions and their given standard reduction potential values: Ox: Sn (s) Sn²+ (aq, 1.50 mol L-1) +2 e¯ E° anode = -0.14 (V) Red: CIO2 (g, 0.270 bar) +e¯ → ClO, (aq, 1.80 mol L-!) Eº cathode = 0.95 (V)

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Chapter1: Chemical Foundations
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An electrochemical cell is based on these two half-reactions and their given standard reduction potential values:
Ox: Sn (s)
Red: C1O2 (g, 0.270 bar) + e¯ → Cio, (aq, 1.80 mol L-1) Eathode = 0.95 (V)
→ Sn²+ (aq, 1.50 mol L-1) +2 e-
E°
= -0.14 (V)
'anode
%3D
Part A
Compute the cell potential at 25 °C.
Express your answer to two decimal places and include the appropriate units.
µA
圈]
?
Ecell = 1.01
V
Submit
Previous Answers Request Answer
X Incorrect; Try Again; One attempt remaining
Review your calculations and make sure you round to 3 significant figures in the last step.
Transcribed Image Text:An electrochemical cell is based on these two half-reactions and their given standard reduction potential values: Ox: Sn (s) Red: C1O2 (g, 0.270 bar) + e¯ → Cio, (aq, 1.80 mol L-1) Eathode = 0.95 (V) → Sn²+ (aq, 1.50 mol L-1) +2 e- E° = -0.14 (V) 'anode %3D Part A Compute the cell potential at 25 °C. Express your answer to two decimal places and include the appropriate units. µA 圈] ? Ecell = 1.01 V Submit Previous Answers Request Answer X Incorrect; Try Again; One attempt remaining Review your calculations and make sure you round to 3 significant figures in the last step.
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