An electric heater consists of a single resistor connected across 110 V. It is used to heat 200.0 g of water in a coffee cup from 20°C to 90°C in 2.70 min. 1) Assuming that 90% of the energy drawn from the power source goes into heating the water, what is the resistance of the heater? Use c = 4186 J/kg-K (Express your answer to two significant figures.) 30.1 2Submit 2) Assuming no other heat losses, how much longer will it take to heat your water if you had to power the water heater with your 12.0-V car battery? (Express your answer to two significant figures.) h Submit

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Please provide an answer to part B. 3.3, 3.35, 3.4 hours are all being marked as incorrect.
An electric heater consists of a single resistor connected across 110 V. It is used to heat 200.0 g of water in a coffee cup
from 20°C to 90°C in 2.70 min.
1) Assuming that 90% of the energy drawn from the power source goes into heating the water, what is the resistance of
the heater? Use c = 4186 J/kg-K (Express your answer to two significant figures.)
30.1
2Submit
2) Assuming no other heat losses, how much longer will it take to heat your water if you had to power the water heater
with your 12.0-V car battery? (Express your answer to two significant figures.)
h Submit
+)
Transcribed Image Text:An electric heater consists of a single resistor connected across 110 V. It is used to heat 200.0 g of water in a coffee cup from 20°C to 90°C in 2.70 min. 1) Assuming that 90% of the energy drawn from the power source goes into heating the water, what is the resistance of the heater? Use c = 4186 J/kg-K (Express your answer to two significant figures.) 30.1 2Submit 2) Assuming no other heat losses, how much longer will it take to heat your water if you had to power the water heater with your 12.0-V car battery? (Express your answer to two significant figures.) h Submit +)
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