An electric field of 1000 V/m is applied to an electric dipole at angle of 45º. The value of electric dipole moment is 1029 C-m. What is the potential energy of the electric dipole?
Q: A capacitor fully charged by a 6V battery has 12nC of charge stored on its plates. The area of its…
A:
Q: The electric potential difference between two infinite, parallel metal plates is V. If the plates…
A: The potential difference between two plates is 1.104V Thank you Let me know if you have any doubts…
Q: A Van de Graaff generator has a 0.250 m diameter metal sphere that produces a voltage of 100 kV near…
A: Given Diameter = 0.250 m Voltage = 100 kV We have to calculate the excess charge on the surface.
Q: -5.0 µC charge moves from m to m in a uniform electric field V/m. (a) Calculate the potential…
A: charge (q) = -5 μC Initial position = <2,-5,3> mFinal position = <6,3,1> mElectric field…
Q: The dielectric to be used in a parallel-plate capacitor has a dielectric constant of 4.00 and a…
A:
Q: A rubber sheet of infinite size has an area charge density of σ = -48.5 nC/m^2 spread uniformly on…
A: Given:- The electric field is given by the rubber sheet and glass fiber with line…
Q: A parallel-plate air capacitor with a capacitance of 250 pF has a charge of magnitude 0.146 μC on…
A:
Q: Each plate of a parallel-plate air capacitor has an area of 0.0040 m2, and the separation of the…
A: Seen below page sloution
Q: What is the strength of the electric field between two large parallel conducting plates separated by…
A:
Q: If a parallel plate capacitor of 0.100x10-6F using a dielectric material with a constant of k=3.70…
A:
Q: A parallel plate capacitor has a plate area of 21.4 x 10-4 m2 and a plate separation distance of 27…
A:
Q: In building a particle accelerator, you manage to produce a uniform electric field of magnitude 5.03…
A: Given: The magnitude of the electric field is 5.03x105 N/C. The length of the section is 30.5 cm.
Q: A 2.4x10 -9 C charge is initially traveling at a speed of 1.0 x 10 5 m/s in a parallel plate setup.…
A:
Q: A proton (mass = 1.67 x 10-27 kg, charge = 1.60 x 10-19 C) moves from point A to point B under the…
A: Velocity at point A =50 KM/S = 50000 k/s Velocity at point B =82.6 Km/ s = 82600 m/s Q( VA - VB) = W…
Q: uniform electric field of magnitude 400 V/m is directed in the positive x-direction. A 15 µC charge…
A:
Q: Two parallel plates (with a dielectric in between) each have an area of 28.2 cm2. The E-field…
A:
Q: A parallel plate system has a plate separation distance of 18.2 cm. The plates are connected to a…
A:
Q: An electric field does 1.05 ✕ 103 eV of work on a carbon nucleus of charge 9.61 ✕ 10−19 C. Find the…
A:
Q: Two large metal parallel plates carry opposite charges of equal magnitude. They are separated by…
A: Given: Separation between two plates, d=90.0 mm Potential difference, V=180 V To determine: The…
Q: A charge of 81 pC is distributed on an isolated spherical conductor that has a radius of 4 cm .…
A:
Q: The ammonia molecule has a dipole moment of 5.0×10−30 C·m. Ammonia molecules in the gas phase are…
A:
Q: A parallel plate capacitor has a plate area of 0.30m^2 and a plate separation of 0.10mm. If the…
A:
Q: A uniform electric field of magnitude 423 N/C pointing in the positive x-direction acts on an…
A: Electric field (E) = 423 N/C distance moved (d) = 3.40 cm = 0.034 m initial speed (u) = 0 m/s
Q: A uniform electric field of magnitude 277V/m is directly in the positive x-direction. A 1.33E-5C…
A:
Q: A point-like charge Q = 20.5 µC is embedded into a dielectric material with constant k = 20. F…
A:
Q: A uniform electric field of 4.50 kN/C points in the +x direction. 1) What is the change in potential…
A:
Q: A 5.30 cm by 2.40 cm parallel plate capacitor has the plates separated by a distance of 2.00 mm.…
A: The objective of the question is to find the electric field in the dielectric of a parallel plate…
Q: A charge per unit length given by A = 2.40 µC/m is distributed uniformly along the circumference of…
A: Given,
Q: Two parallel plates have equal and opposite charges. When the space between the plates is evacuated,…
A: Given data E0=3.2×105 V/mE1=2.5×105 V/m
Q: The electric field in the region between the plates of a parallel plate capacitor has a magnitude of…
A:
Q: If the electric field inside a capacitor exceeds the dielectric strength of the dielectric between…
A: Dielectric strength of air , Emaxair = 3 x 106 V/m Dielectric strength of neoprene , Emaxneo = 1.2 x…
Q: - An electric field of 1000 V/m is applied to an electric dipole at angle of 45°. The value of…
A:
Q: Two parallel plates with a dielectric (k=3.75) in between are separated by a distance of 2.00 mm.…
A:
Q: Two conductive plates are oriented such that they are exactly parallel to one another and are…
A:


Step by step
Solved in 2 steps

- A uniform electric field of magnitude 395 N/C pointing in the positive x-direction acts on an electron, which is initially at rest. The electron has moved 2.90 cm. (a) What is the work done by the field on the electron? 1.83e-16 Your response is off by a multiple of teh. J (b) What is the change in potential energy associated with the electron? -1.83e-16 Your response is off by a multiple of ten. J (c) What is the velocity of the electron? 2.00e-24 Your response differs significantly from the correct answer. Rework your solution from the beginning and check each step carefully. m/s Select v magnitude direction Need Help? Read Itquestion 9A charged capacitor consisting of two parallel plates has an area and separate of 0.500 m2 and 9.00 mm respectively. If the electric field strength between the plates is 3.0 x 106 Vm-1, calculate the energy stored in the capacitor.
- A parallel-plate capacitor initially has Quartz between its plates and carries charge ±Q. A different dielectric is then inserted between the plates without changing the charge. If the energy stored in the capacitor decreases to 72% of its initial value, what is the value of x for the new dielectric? K =An electric dipole consisting of charges of magnitude 4.70 nC separated by 8.20 um is in an electric field of strength 1100 N/C. What are (a) the magnitude of the electric dipole moment and (b) the difference between the potential energies for dipole orientations parallel and antiparallel to E ? (a) Number i Units (b) Number i UnitsStarting from rest, a proton was accelerated by an electric field. After a distance of 1.35 m the proton reaches a speed of 1.97 x 105 m/s (m, = 1.67 x 10-27 kg, q,= 1.60 x 10-19 C). a) What is the final kinetic energy of the proton? b) What is the potential energy difference of the proton? c) What is the magnitude of the electric field?
- The potential difference between two parallel plates is 598 V. An alpha particle with mass of 6.64×10-27 kg and charge of 3.20×10-19 C is released from rest near the positive plate. a) What is the speed of the alpha particle when it reaches the other plate? The distance between the plates is 36.2 cm.How strong is the electric field in N/C between two parallel plates (5.0000x10^0) mm apart if the potential difference between them is (2.13x10^2) V? Note: Your answer is assumed to be reduced to the highest power possible. Your Answer: x10 AnswerWhat is the magnitude, in volts, of the maximum potential difference between two parallel conducting plates separated by 0.51 cm of air?
- A 5.70 x 10^-16 kg oil drop accelerates upward at a rate of 2.90 m/s^2 when placed between two horizontal, parallel plates that are 3.50 cm apart. If the potential difference between the plates is 7.92 x 10^2 V, what is the magnitude of the charge on the oil drop?The electric field in a region of space has the components Ey = Ez = 0 and Ex = (4.00 N/C · m) x. Point A is on the y axis at y = 3.60 m, and Point B is on the x axis at x = 4.40 m. What is the potential difference between VB − and VA?Two parallel plates have equal and opposite charges. When the space between the plates is evacuated, the electric field is E= 3.30×105 V/m. When the space is filled with dielectric, the electric field is E= 2.50×105 V/m. For related problem-solving tips and strategies, you may want to view a Video Tutor Solution of Energy density, both before and after the. What is the charge density on each surface of the dielectric? Express your answer in coulombs per meter squared. να ΑΣΦ ? |X| X•10" |oi| = C/m²