An electric field given by E = 3.5 i - 3.0(y2 + 2.0) j pierces the Gaussian cube of Figure 23-05. (E is in newtons per coulomb and x is in meters.) What is the electric flux through the following surfaces?

An electric field given by E = 3.5 i - 3.0(y2 + 2.0) j pierces the Gaussian cube of Figure 23-05. (E is in newtons per coulomb and x is in meters.) What is the electric flux through the following surfaces?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter24: Gauss’s Law

Section: Chapter Questions

Problem 24.46P: A thin, square, conducting plate 50.0 cm on a side lies in the xy plane. A total charge of 4.00 108...

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Question

An electric field given by E = 3.5 i - 3.0(y² + 2.0) j pierces the Gaussian cube of Figure 23-05. (E is in newtons per coulomb and x is in meters.) What is the electric flux through the following surfaces?

An electric field given by E = 3.5 i - 3.0(y2 + 2.0) j pierces the Gaussian cube of Figure 23-05. (E is in newtons per coulomb and x is in meters.) What is the electric flux through the following
surfaces?
Gaussian
surface
x= 1.0 m x = 3.0 m
Fig. 23-05
(a) the top face
N•m2/c
(b) the bottom face
|N•m2/c
(c) the left face
|N•m?/c
(d) the back face
|N•m2/c
(e) the net electric flux through the cube
|N•m?/c
(f) What is the net electric charge inside the box?
(g) What are the units of the constant 3.0 in the expression for electric field?

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