An electric dipole with dipole moment p = 6 × 10¯5 C · m sets up an electric field (in newtons per coulomb) kp -(3xz, 3yz, 2z² – x² - y²) r5 F(x, y, z) = 1/2 where r = (x² + y² + 2²)¹22 with distance in meters and k = 8.99 × 10⁹ N-m². Calculate the work against F required to move a particle of charge q = 0.01 C from (1, -5,0) to (4, 2, 2). Note: The force on q is qF newtons. (Use decimal notation. Give your answer to one decimal place.) W≈ J

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