An electric dipole with atomic charges +q and -q are fixed to the ends of a rigid neutral molecule with length. The mass of the charges are Nm and the mass of the rigid rod-like molecule is M, note that N is the number of nucleons in each of the two charged atoms. The electric dipole is set Find oscillating in a uniform electric field, E. The net torque exerted on the dipole is 7 = 7x E. the simple harmonic oscillation equation for the orientation of the dipole, the solution to the D.E., and the angular frequency in terms of the given information. Be sure to include all undetermined coefficients.

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An electric dipole with atomic charges +q and -q are fixed to the ends of a rigid neutral molecule
with length . The mass of the charges are Nm and the mass of the rigid rod-like molecule is M,
note that N is the number of nucleons in each of the two charged atoms. The electric dipole is set
oscillating in a uniform electric field, E. The net torque exerted on the dipole is 7=7 xE. Find
the simple harmonic oscillation equation for the orientation of the dipole, the solution to the D.E.,
and the angular frequency in terms of the given information. Be sure to include all undetermined
coefficients.
Transcribed Image Text:An electric dipole with atomic charges +q and -q are fixed to the ends of a rigid neutral molecule with length . The mass of the charges are Nm and the mass of the rigid rod-like molecule is M, note that N is the number of nucleons in each of the two charged atoms. The electric dipole is set oscillating in a uniform electric field, E. The net torque exerted on the dipole is 7=7 xE. Find the simple harmonic oscillation equation for the orientation of the dipole, the solution to the D.E., and the angular frequency in terms of the given information. Be sure to include all undetermined coefficients.
Nm
тяг
IA
Ip+Ip = 2 Nm 12
4
2
4
12
So total moment of inertian = I = M₁²
l... Mymeral
given 0(t) (the value)
0 (t) = Omax Sin (w(+a)
Like 6(t=0)
6 (t = 0)
G
de (t)
1= w Ommy cos (wt tu)
dt
do (t) (a Valve
At
2
2
Z
OH) = 0
may sin (wt+4)
cos² (wt +4)
mmx
max
2
0
of max
1/2
OH) + (616) / 1)² ]
W
sin (wtta)
ton & if t=0
Cos (wttu)
one can solve even if tto.
Solve for
Const
A
+
2 را
& max
616)
616)/w
2
-10
[
1
+0
✓
+ Nil²
2
Transcribed Image Text:Nm тяг IA Ip+Ip = 2 Nm 12 4 2 4 12 So total moment of inertian = I = M₁² l... Mymeral given 0(t) (the value) 0 (t) = Omax Sin (w(+a) Like 6(t=0) 6 (t = 0) G de (t) 1= w Ommy cos (wt tu) dt do (t) (a Valve At 2 2 Z OH) = 0 may sin (wt+4) cos² (wt +4) mmx max 2 0 of max 1/2 OH) + (616) / 1)² ] W sin (wtta) ton & if t=0 Cos (wttu) one can solve even if tto. Solve for Const A + 2 را & max 616) 616)/w 2 -10 [ 1 +0 ✓ + Nil² 2
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