An electric dipole р-бах- Зау+2аx nС-m is located at (-1,2,-3). Find the potential at point (3,-9,4).
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A: Given:Capacitance C = 155 μF C = 155 × 10-6 F (convert microfarads to farads)Voltage V = 104 V
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A: Given: The charges of dipole q = +3.0 nC, -3.0 nC. Distance between dipole charges (d) = 4.0 cm.
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A: Given data: Position of point A, r1=3i+6j Position of point B, r2=5i+7j
Q: Will the electric field strength between two parallel conducting plates exceed the breakdown…
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Q: 8. A capacitor has square plates, each of side a, making an angle with each other as shown in Fig.…
A: Length of the capacitor plates=a minimum distance between the plates=d Angle one plate makes with…
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- An electric dipole p=6ax-3ay+2ax nC-m is located at (-1,2,-3). Find the potential at point (3,-9,4).fig 5 Me= In Figure 5. the electron on the right side is fixed. and the one on the left side has initial velocity 10' m/s towards the first electron at the distance shown. Determine the final speed of the mobile electron when it is far away from the fixed one.Asap
- Each cord can sustain a maximum tension of 31 lb. (Figure 1) Part A Determine the largest weight of the lamp that can be supported. Express your answer to three significant figures and include the appropriate units. ? HA W = Value Units Submit Request Answer Figure 1 of 1 Part B E Determine 0 of cord DC for equilibrium. 30° Express your answer using three significant figures. B 60° Αφ vec ? Submit Request AnswerThe clectric potential in a region of space is V (x, y) 200 Volts, where x and x²+y² y are in meters. What are the strength and direction of the clectric ficld at (x, y) = (2.0 m, 2.0 m)? Give the direction as an angle cw or ccw (specify which) from the positive r-axis.Calculate the capacitance of a pair of parallel plates 10 cm by 10 cm with an air gap of 3.4 mm.Use vacuum permittivity ε0 = 8.85 × 10−12 F/m, for air εr = 1.
- Calculate the capacitance of a pair of parallel plates 10 cm by 10 cm with an air gap of 3.4 mm. Use vacuum permittivity ɛo = 8.85 × 10¬12 F/m, for air ɛ, 1. Provide your answer in units of 10¬15 F: for example, if your answer is 5 x 10¬12 F, then enter 50 as your answer.(a) Starting from Coulomb’s law, show that the electric potential a distance r from a point charge q is given by V= q/ 4πε0r (b) Four point charges are assembled as shown in Fig. Calculate the potential energy of this configuration (you may assume that the chargesare isolated and in a perfect vacuum). Does the potential energy dependupon the order in which the charges are assembled? Is the charge configuration in (b) stable?find the maximum potential difference between two parallel conducting plates separated by 0.45cm of air, given the maximum sustainable electric field strength in air to be 3.00mv/m. Answer in kV.
- (a) Determine the electric field strength between two parallel conducting plates to see if it will exceed the breakdown strength for air (3 ✕ 106 V/m). The plates are separated by 3.48 mm and a potential difference of 5515 V is applied. V/m(b) How close together can the plates be with this applied voltage without exceeding the breakdown strength? mmA dielectric- filled por allel-plate capacitor as pleite area A=10.0cm²,plate separation d= 8.00 mm an K = 4•00. The capacitor is connected to a battery oltage V= 5•00 V Throughout nd dieleitric tonštad that creates a the problem, use constant ve -12 U, of the dielect erically in joules d मास्पु Find the ric - filled copacitor energy つ) मा र #he txpress your an Swer nu 2 The dielectric plaite i's now slewly pulled eut of the capacater, which rencains connected to the battery. tind the energy Uz ator at the moment when the Lapecitor is capa half-filled with Hhe dielectric. Express your answers nuimerically in joules 3.The capecitor s Row disconnected from the battery and the dielectric plate is slowly removed the rest ef Hhe way out ef the capacitor. find the new enerqy ef he capecitor Ug Express your answers ruemerically ie joules 4.J0the the dielectric from the disconnected work Wis done by e exter nal ager frocess of removing The remaining pertion ef the capacitor, how much nt ating…Find the equivalent capacitance