An electric dipole consists of two charges of equal magnitude and opposite sign separated by a distance 2a as shown in the figure below. The dipole is along the x axis and is centered at the origin. R The electric potential at point R on the positive x axis is given by the following equation: 2kega VR = ke + x + a %3D When x is much greater than a, the following approximation can be used: (- 2kega 2kega VR = lim X>>a (x >> a) (a) Use the information above to find the electric potential created by the dipole described above at the point (3a, 0). (Use any variable or symbol stated above along with the following as necessary: ke.) V = (b) By what percentage does your answer differ from the result of the approximate expression that is valid when x is much greater than a.

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Chapter1: Units, Trigonometry. And Vectors
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An electric dipole consists of two charges of equal magnitude and opposite sign separated by a distance 2a as shown in the figure below. The dipole is along the x axis and is centered at the
origin.
y
a
a
R
-9
The electric potential at point R on the positive x axis is given by the following equation:
VR = ke L9i
ri
2kega
x2 – a?
b.
ke
х — а
+
х+а
i
When x is much greater than a, the following approximation can be used:
VR = lim
X>>a
2keqa
x2 – a2
2kega
x2
(x >> a)
(a) Use the information above to find the electric potential created by the dipole described above at the point (3a, 0). (Use any variable or symbol stated above along with the
following as necessary: ke.)
V =
(b) By what percentage does your answer differ from the result of the approximate expression that is valid when x is much greater than a.
%
Transcribed Image Text:An electric dipole consists of two charges of equal magnitude and opposite sign separated by a distance 2a as shown in the figure below. The dipole is along the x axis and is centered at the origin. y a a R -9 The electric potential at point R on the positive x axis is given by the following equation: VR = ke L9i ri 2kega x2 – a? b. ke х — а + х+а i When x is much greater than a, the following approximation can be used: VR = lim X>>a 2keqa x2 – a2 2kega x2 (x >> a) (a) Use the information above to find the electric potential created by the dipole described above at the point (3a, 0). (Use any variable or symbol stated above along with the following as necessary: ke.) V = (b) By what percentage does your answer differ from the result of the approximate expression that is valid when x is much greater than a. %
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