An electric dipole consists of charges +2e and -2e separated by 1.1 nm. It is in an electric field of strength 3.1 × 10° N/C. Calculate the magnitude of the torque on the dipole when the dipole moment is (a) parallel to, (b) perpendicular to, and (c) antiparallel to the electric field.
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- A particle (mass =67x 10 kg charge = +3.2 x 10" C) moves along the positive x axis with a speed of 4.8x 10 m/s. It enters a region of uniform electric field parallel to its motion and comes to rest after moving 20 m into the field. What is the magnitude of the electric field?An electric dipole has charges of +2e and -2e and are separated by 0.78nm. The dipole sits in an electric field of 3.4 x 106 N/C. What is the torque on the dipole if the dipole moment is: a) parallel to the electric field? b) perpendicular to the electric field? c) antiparallel(180 degrees) to the electric field?Three point charges lie along a straight line as shown in the figure below, where q₂ = 6.54 μC, 92 = 1.38 µC, and q3 = -1.94 μC. The separation distances are d₁ = 3.00 cm and d₂ = 2.00 cm. Calculate the magnitude and direction of the net electric force on each of the charges. esc (a) q₁ 91 magnitude N direction to the left ✔ 1 (b) 9₂ - magnitude direction to the right (c) Q3 Need Help? Read I magnitude N direction to the left ✔ 1 / 92 Q A N FI N @ 2 W S X H command 93 -83 G 3 E D 20 F3 C $ 4 F4 R F V 25 % FS T G ^ 6 B MacBook Air FG Y H & 7 N F7 U J * 00 8 DII FB 1 M ( 9 K F9 O < H ) O L F10 command P ; F11 + 11 [ option 11 1 F12 1 delete
- The figure below shows a charged particle, with a charge of q = +38.0 nC, that moves a distance of d = 0.185 m from point A to point B in the presence of a uniform electric field E of magnitude 245 N/C, pointing right. A positive point charge q is initially at point A, then moves a distance d to the right to point B. Electric field vector E points to the right. (a) What is the magnitude (in N) and direction of the electric force on the particle? magnitude Ndirection ---Select--- toward the right toward the left The magnitude is zero. (b) What is the work (in J) done on the particle by the electric force as it moves from A to B? J (c) What is the change of the electric potential energy (in J) as the particle moves from A to B? (The system consists of the particle and all its surroundings.) PEB − PEA = J (d) What is the potential difference (in V) between A and B? VB − VA = VTwo parallel, uniformly charged, infinitely long wires carry opposite charges with a linear charge density λ = 1.00 μC/m and are 4.22 cm apart. What is the magnitude of the electric field at a point midway between them and 44.2 cm above the plane containing the two wires?An electric dipole with dipole moment 4×10−9 Cm is aligned at 30° with the direction of a uniform electric field of magnitude 5×104 NC−1. Calculate the magnitude of the torque acting on the dipole.
- can you please ans (d), (e), (f), (g)?(a) Three point charges, A = 1.50 µC, B = 7.50 µC, and C = -3.80 µC, are located at the corners of an equilateral triangle as in the figure above. Find the magnitude and direction of the electric field at the position of the 1.50 µC charge. magnitude directionIn the figure a uniform, upward electric field of magnitude 1.60 × 103 N/C has been set up between two horizontal plates by charging the lower plate positively and the upper plate negatively. The plates have length L = 17.0 cm and separation d = 1.70 cm. An electron is then shot between the plates from the left edge of the lower plate. The initial velocity of the electron makes an angle 0 = 45.0° with the lower plate and has a magnitude of 6.40 × 105 m/s. (a) Will the electron strike one of the plates? (b) If so, which plate, top or bottom? (c) How far horizontally from the left edge will the electron strike? ↑E 5%8 (a) (b) (c) Number Mr Units <