An ecologist wishes to mark off a circular sampling region having radius 10 m. However, the radius of the resulting region is actually a random variable R with the following pdf.f(r)= 4(10-r)²]Xm09 ≤ r ≤ 11otherwiseWhat is the expected area of the resulting circular region? (Round your answer to two decimal places.)9.99m²

Answered: Image /qna-images/answer/81d319f1-dea1-40b4-860b-724ab52d5f22.jpg

Answered: An ecologist wishes to mark off a…

Advanced Engineering Mathematics

10th Edition

ISBN:9780470458365

Author:Erwin Kreyszig

Publisher:Erwin Kreyszig

Chapter2: Second-order Linear Odes

Section: Chapter Questions

Problem 1RQ

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22
Please help. I’m trying to complete these problems as review and they’re stumping me. No code please just math
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A company wants to determine whether it's consumer product ratings (0-10) have changed from last year to this year. The table below shows the company's product ratings from 8 consumers for last year and this year. At a=0.05, is there enough evidence to conclude that the ratings have changed? Assume the samples are random and dependent, and the population is normally distributed. Complete parts A-F.
26 The table to the right shows the cost per ounce (in dollars) for a random sample of toothpastes exhibiting very good stain removal, good stain removal, and fair stain removal. At α=0.01, can you conclude that the mean costs per ounce are different? Perform a one-way ANOVA test by completing parts a through d. Assume that each sample is drawn from a normal population, that the samples are independent of each other, and that the populations have the same variances. Very good stain removal Good stain removal Fair stain removal 0.37 0.75 0.60 0.49 2.66 1.18 0.33 0.46 0.46 1.64 0.33 0.50 0.58 0.41 1.39 (b) Identify the degrees of freedom for the numerator and for the denominator, determine the critical value, and determine the rejection region. The degrees of freedom for the numerator, d.f.N, is ____ and the degrees of freedom for the denominator, d.f.D, is _____ The critical…
For a population with a = 12, how large a sample is necessary to have a standard error that is less than 4 points? n > ?
You take a simple random sample of size 25 from a very large population in which the true proportioni p=0.1. Which statement below best describes what you know about the sampling distribution of p? (0.1)(0.9) (a) H,-0.1; o,- the distribution is skewed right. 25 (0.1)(0.9). 25 (b) H,=0.1; o,=. ; the distribution is skewed left. (0.1)(0.9). (c) ,=0.1; o,= the distribution is approximately Normal. %3D 25 (0.1)(0.9) (d) , the distribution is not approximately Normal. 25 =0.1; we cannot use the formula o, (0.1)(0.9) ; the distribution is approximately Normal. 25 (e) =0.1; we cannot use the formula o,
Determine the rejection region for a hypothesis test for the population mean using the give information. Assume that the population standard deviation is unknown, the sample size is small, and the population distribution is approximately normal. Write your answer in a format exactly as in the following examples, "t <= -2.203", or "t >= 1.706", or "|t| >= 1.305". Do not forget the SPACE after t and the SPACE before the number. Also make sure to enter the digit 0 before the decimal point. ?=0.90,??=18 two-tailed test Reject H0 if
Use the data in the Excel workbook, on the worksheet labeled "Sample," for this question. The first column is just an observation index labeled i to name each observation. The observations are a simple random sample with replacement from a much larger population. The second column contains specific values y of a random variable Y found in some sampled population. The population standard deviation is not known to you, but it is known that Y has a Normal distribution in the sampled population. Compute the lower bound of an 85% confidence interval for the population mean of the random variable Y. i y 1 37 2 40 3 31 4 27 5 23 6 33 7 29 8 26 9 39 10 28 11 34 12 39 13 31 14 34 15 39 16 33 17 31 18 42
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A random sample of size 10 yielded roughly "mound-shaped" data with a sample mean of 63.5 and a sample variance of 60.8. Let (L, OU) be the interval estimate that contains the population mean with 95% probability. Find the width of the interval. That is, find 0 – 0₁. 4.52 5.49 5.58 5.70 9.04 10.99 11.16 11.40 none of the other answers give the correct width

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