helpppp **Problem Statement**An earthquake causes a piece of glass to fall off a building from a height of 2,704 ft. If the equation for height as a function of time is\[ h(t) = -16t^2 + \text{initial\_height} \]where \( t \) is time in seconds and \( h(t) \) is height in feet, how many seconds will it take for the piece of glass to hit the ground?**Solution**To solve this problem, we start with the given height equation:\[ h(t) = -16t^2 + \text{initial\_height} \]In this specific problem:- The initial height is 2,704 feet.So, the height equation is:\[ h(t) = -16t^2 + 2704 \]We need to determine the time \( t \) when the piece of glass hits the ground. This occurs when the height \( h(t) \) is 0:\[ 0 = -16t^2 + 2704 \]Solving for \( t \):1. Isolate the \( t^2 \) term: \[ 16t^2 = 2704 \]2. Divide both sides by 16: \[ t^2 = 169 \]3. Take the square root of both sides: \[ t = \sqrt{169} \]\[ t = 13 \]Therefore, it will take 13 seconds for the piece of glass to hit the ground.

Name: helpppp **Problem Statement**An earthquake causes a piece of glass to
Uploaded: 2024-03-05T11:52:21.000Z
Channel: Bartleby
Description: helpppp **Problem Statement**An earthquake causes a piece of glass to fall off a building from a height of 2,704 ft. If the equation for height as a function of time is\[ h(t) = -16t^2 + \text{initial\_height} \]where \( t \) is time in seconds and \