College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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can you help me get the answer below, with steps.
Transcribed Image Text:**Question:**
What is the work done by the 40-N force? What work is done by the spring? What is the resultant work?
**Answer:**
2.40 J, –2.40 J, 0
![### Physics Problem: Work Done on a Spring
**Problem 8.9:**
An average force of 40 N compresses a coiled spring a distance of 6 cm. What is the work done?
---
This text appears under "Chapter 8" in the "Summary and Review" section on page 174.
### Explanation:
To find the work done on the spring, use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Given:
- Force (\( F \)) = 40 N
- Distance (\( d \)) = 6 cm = 0.06 m (converted to meters for standard units)
Substitute the values into the formula:
\[ \text{Work} = 40 \, \text{N} \times 0.06 \, \text{m} \]
\[ \text{Work} = 2.4 \, \text{Joules} \]
Thus, the work done in compressing the spring is 2.4 Joules.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fcee2c121-2b0c-4869-8ee3-9137b5f2d7c4%2F7bc2c685-60d4-4a36-9bc7-7eae6a7134af%2Frgdba6_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Physics Problem: Work Done on a Spring
**Problem 8.9:**
An average force of 40 N compresses a coiled spring a distance of 6 cm. What is the work done?
---
This text appears under "Chapter 8" in the "Summary and Review" section on page 174.
### Explanation:
To find the work done on the spring, use the formula for work:
\[ \text{Work} = \text{Force} \times \text{Distance} \]
Given:
- Force (\( F \)) = 40 N
- Distance (\( d \)) = 6 cm = 0.06 m (converted to meters for standard units)
Substitute the values into the formula:
\[ \text{Work} = 40 \, \text{N} \times 0.06 \, \text{m} \]
\[ \text{Work} = 2.4 \, \text{Joules} \]
Thus, the work done in compressing the spring is 2.4 Joules.
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