An autosomal recessive disease affects /200 dogs and the populadion is in Hardy-wenborg. a) what proporton of the poularon are cauners for the diseOse? b) A carrrer dog and an unknown dog are randomy saected from the popucaion and thoy have one offiring what is the foosibility the offspring is a carrier for tme disease?

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### Genetics Problem Set

#### Problem Description:
An autosomal recessive disease affects 1/200 dogs and the population is in Hardy-Weinberg equilibrium.

a) What proportion of the population are carriers for the disease?

b) A carrier dog and an unknown dog are randomly selected from the population and they have one offspring. What is the possibility the offspring is a carrier for the disease?

### Explanation:

#### a) Proportion of Carriers in the Population

Given:
- The disease is autosomal recessive.
- It affects 1 out of 200 dogs in the population.

To determine:
- The proportion of carriers (heterozygotes) in the population.

#### b) Probability the Offspring is a Carrier

Given:
- One parent is a carrier (heterozygote) and the other parent is selected randomly from the population.
- Determine the probability that the offspring will be a carrier for the disease.

#### Detailed Explanation:

**a) Calculation of Carrier Proportion:**

1. Let q be the frequency of the recessive allele.
2. The frequency of the recessive phenotype (affected dogs) = q² = 1/200.
3. Solve for q: 
\[ q = \sqrt{\frac{1}{200}} \].
4. Use Hardy-Weinberg principle: 
\[ \text{Proportion of carriers} = 2pq \]
where p is the frequency of the dominant allele (p + q = 1).

**b) Calculation of Probability of Carrier Offspring:**

1. First, calculate q (as in part a).
2. Determine the possible genotypes of the randomly selected parent (AA, Aa, aa) and their frequencies.
3. Use Punnett squares to determine the probability of the offspring being a carrier (Aa).

This exercise requires understanding of the Hardy-Weinberg equilibrium, solving quadratic equations, and basic probability concepts.
Transcribed Image Text:### Genetics Problem Set #### Problem Description: An autosomal recessive disease affects 1/200 dogs and the population is in Hardy-Weinberg equilibrium. a) What proportion of the population are carriers for the disease? b) A carrier dog and an unknown dog are randomly selected from the population and they have one offspring. What is the possibility the offspring is a carrier for the disease? ### Explanation: #### a) Proportion of Carriers in the Population Given: - The disease is autosomal recessive. - It affects 1 out of 200 dogs in the population. To determine: - The proportion of carriers (heterozygotes) in the population. #### b) Probability the Offspring is a Carrier Given: - One parent is a carrier (heterozygote) and the other parent is selected randomly from the population. - Determine the probability that the offspring will be a carrier for the disease. #### Detailed Explanation: **a) Calculation of Carrier Proportion:** 1. Let q be the frequency of the recessive allele. 2. The frequency of the recessive phenotype (affected dogs) = q² = 1/200. 3. Solve for q: \[ q = \sqrt{\frac{1}{200}} \]. 4. Use Hardy-Weinberg principle: \[ \text{Proportion of carriers} = 2pq \] where p is the frequency of the dominant allele (p + q = 1). **b) Calculation of Probability of Carrier Offspring:** 1. First, calculate q (as in part a). 2. Determine the possible genotypes of the randomly selected parent (AA, Aa, aa) and their frequencies. 3. Use Punnett squares to determine the probability of the offspring being a carrier (Aa). This exercise requires understanding of the Hardy-Weinberg equilibrium, solving quadratic equations, and basic probability concepts.
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