An automobile is depreciating at 11% per year every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89). What is an equivalent equation for this vehicle at a daily depreciation, and what is it worth (rounded to the nearest dollar) 5 years after purchase? O 30,000(0.89) 365t, $16,752 O 30,000(0.9997)*, $29,955 O 30,000(0.9997) 365t, $17,350 O 30,000(1.00026)365, $48, 213

An automobile is depreciating at 11% per year every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89). What is an equivalent equation for this vehicle at a daily depreciation, and what is it worth (rounded to the nearest dollar) 5 years after purchase? O 30,000(0.89) 365t, $16,752 O 30,000(0.9997)*, $29,955 O 30,000(0.9997) 365t, $17,350 O 30,000(1.00026)365, $48, 213

Trigonometry (11th Edition)

11th Edition

ISBN:9780134217437

Author:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher:Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Chapter1: Trigonometric Functions

Section: Chapter Questions

Problem 1RE: 1. Give the measures of the complement and the supplement of an angle measuring 35°.

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Question

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An automobile is depreciating at 11% per year every year. A $30,000 car depreciating at this rate can be modeled by the equation V(t) = 30,000(0.89)¹. What is an
equivalent equation for this vehicle at a daily depreciation, and what is it worth (rounded to the nearest dollar) 5 years after purchase?
30, 000(0.89) 365t, $16,752
30,000(0.9997), $29,955
30,000 (0.9997) 365t, $17,350
30, 000(1.00026) 365t, $48, 213

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