An automobile engine consumes fuel at a rate of 22 L/h and delivers 65 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.8 g/cm³, determine the efficiency of this engine. The efficiency of the engine is %.
An automobile engine consumes fuel at a rate of 22 L/h and delivers 65 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.8 g/cm³, determine the efficiency of this engine. The efficiency of the engine is %.
Elements Of Electromagnetics
7th Edition
ISBN:9780190698614
Author:Sadiku, Matthew N. O.
Publisher:Sadiku, Matthew N. O.
ChapterMA: Math Assessment
Section: Chapter Questions
Problem 1.1MA
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Question
![**Problem Statement:**
An automobile engine consumes fuel at a rate of 22 L/h and delivers 65 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.8 g/cm³, determine the efficiency of this engine.
**Objective:**
Calculate the efficiency of the engine.
**Solution Approach:**
1. **Convert fuel consumption to kg/h:**
\[
\text{Density} = 0.8 \text{ g/cm}^3 = 0.8 \text{ kg/L}
\]
\[
\text{Fuel consumption in kg/h} = 22 \text{ L/h} \times 0.8 \text{ kg/L} = 17.6 \text{ kg/h}
\]
2. **Calculate the energy content of the fuel consumed per hour:**
\[
\text{Energy content (kJ/h)} = 17.6 \text{ kg/h} \times 44,000 \text{ kJ/kg} = 774,400 \text{ kJ/h}
\]
3. **Convert power to kJ/h:**
\[
\text{Power (kJ/h)} = 65 \text{ kW} \times 3600 \text{ s/h} = 234,000 \text{ kJ/h}
\]
4. **Determine the efficiency:**
\[
\text{Efficiency} = \left(\frac{\text{Power output}}{\text{Energy input}}\right) \times 100
\]
\[
\text{Efficiency} = \left(\frac{234,000}{774,400}\right) \times 100 \approx 30.21\%
\]
**Conclusion:**
The efficiency of the engine is approximately **30.21%**.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F7f972ef6-2f1d-41d2-9ff1-9489b939766a%2F92b2d220-d9f4-47f3-8f23-612bf7212d6a%2Ft2ywq1_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An automobile engine consumes fuel at a rate of 22 L/h and delivers 65 kW of power to the wheels. If the fuel has a heating value of 44,000 kJ/kg and a density of 0.8 g/cm³, determine the efficiency of this engine.
**Objective:**
Calculate the efficiency of the engine.
**Solution Approach:**
1. **Convert fuel consumption to kg/h:**
\[
\text{Density} = 0.8 \text{ g/cm}^3 = 0.8 \text{ kg/L}
\]
\[
\text{Fuel consumption in kg/h} = 22 \text{ L/h} \times 0.8 \text{ kg/L} = 17.6 \text{ kg/h}
\]
2. **Calculate the energy content of the fuel consumed per hour:**
\[
\text{Energy content (kJ/h)} = 17.6 \text{ kg/h} \times 44,000 \text{ kJ/kg} = 774,400 \text{ kJ/h}
\]
3. **Convert power to kJ/h:**
\[
\text{Power (kJ/h)} = 65 \text{ kW} \times 3600 \text{ s/h} = 234,000 \text{ kJ/h}
\]
4. **Determine the efficiency:**
\[
\text{Efficiency} = \left(\frac{\text{Power output}}{\text{Energy input}}\right) \times 100
\]
\[
\text{Efficiency} = \left(\frac{234,000}{774,400}\right) \times 100 \approx 30.21\%
\]
**Conclusion:**
The efficiency of the engine is approximately **30.21%**.
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