An automobile antifreeze solution contains 2.70 kg of ethylene glycol, CH2OHCH2 OH , and 1.90 kg of water. Find the mole fraction of ethylene glycol in this solution. What is the mole fraction of water? Mole fraction of ethylene glycol = Mole fraction of water =
An automobile antifreeze solution contains 2.70 kg of ethylene glycol, CH2OHCH2 OH , and 1.90 kg of water. Find the mole fraction of ethylene glycol in this solution. What is the mole fraction of water? Mole fraction of ethylene glycol = Mole fraction of water =
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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![**Problem Statement:**
An automobile antifreeze solution contains 2.70 kg of ethylene glycol, \( \text{CH}_2\text{OHCH}_2\text{OH} \), and 1.90 kg of water. Find the mole fraction of ethylene glycol in this solution. What is the mole fraction of water?
**Objective:**
Calculate the following:
- Mole fraction of ethylene glycol
- Mole fraction of water
**Solution Steps:**
1. **Calculate the number of moles of each component:**
- **Ethylene glycol (\( \text{CH}_2\text{OHCH}_2\text{OH} \)):**
- Molar mass = 62.07 g/mol
- Mass = 2.70 kg = 2700 g
\[
\text{Moles of ethylene glycol} = \frac{2700 \text{ g}}{62.07 \text{ g/mol}}
\]
- **Water (\( \text{H}_2\text{O} \)):**
- Molar mass = 18.02 g/mol
- Mass = 1.90 kg = 1900 g
\[
\text{Moles of water} = \frac{1900 \text{ g}}{18.02 \text{ g/mol}}
\]
2. **Calculate the mole fractions:**
- **Total moles = Moles of ethylene glycol + Moles of water**
- **Mole fraction of ethylene glycol:**
\[
\text{Mole fraction of ethylene glycol} = \frac{\text{Moles of ethylene glycol}}{\text{Total moles}}
\]
- **Mole fraction of water:**
\[
\text{Mole fraction of water} = \frac{\text{Moles of water}}{\text{Total moles}}
\]
**Outputs:**
- Mole fraction of ethylene glycol
- Mole fraction of water
Use the above methods to calculate the specific mole fractions for ethylene glycol and water based on the provided masses.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fc57e455c-e356-45e8-9424-9ece1c8d9714%2F962776c6-47f9-44b8-b0ba-601dd67f8036%2Fnqn1r7n_processed.png&w=3840&q=75)
Transcribed Image Text:**Problem Statement:**
An automobile antifreeze solution contains 2.70 kg of ethylene glycol, \( \text{CH}_2\text{OHCH}_2\text{OH} \), and 1.90 kg of water. Find the mole fraction of ethylene glycol in this solution. What is the mole fraction of water?
**Objective:**
Calculate the following:
- Mole fraction of ethylene glycol
- Mole fraction of water
**Solution Steps:**
1. **Calculate the number of moles of each component:**
- **Ethylene glycol (\( \text{CH}_2\text{OHCH}_2\text{OH} \)):**
- Molar mass = 62.07 g/mol
- Mass = 2.70 kg = 2700 g
\[
\text{Moles of ethylene glycol} = \frac{2700 \text{ g}}{62.07 \text{ g/mol}}
\]
- **Water (\( \text{H}_2\text{O} \)):**
- Molar mass = 18.02 g/mol
- Mass = 1.90 kg = 1900 g
\[
\text{Moles of water} = \frac{1900 \text{ g}}{18.02 \text{ g/mol}}
\]
2. **Calculate the mole fractions:**
- **Total moles = Moles of ethylene glycol + Moles of water**
- **Mole fraction of ethylene glycol:**
\[
\text{Mole fraction of ethylene glycol} = \frac{\text{Moles of ethylene glycol}}{\text{Total moles}}
\]
- **Mole fraction of water:**
\[
\text{Mole fraction of water} = \frac{\text{Moles of water}}{\text{Total moles}}
\]
**Outputs:**
- Mole fraction of ethylene glycol
- Mole fraction of water
Use the above methods to calculate the specific mole fractions for ethylene glycol and water based on the provided masses.
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