An Atwood's machine consists of blocks of masses m, = 11.0 kg and m, = 19.0 kg attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 9.60 kg and radius r = 0.200 m. The block of mass m, is allowed to drop, and the cord turns the pulley without slipping. T2 тi т2 (a) Why must the tension T, be greater than the tension T,? This answer has not been graded yet. (b) What is the acceleration of the system, assuming the pulley axis is frictionless? (Give the magnitude of a.) m/s? (c) Find the tensions T, and T2 T2 =
An Atwood's machine consists of blocks of masses m, = 11.0 kg and m, = 19.0 kg attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 9.60 kg and radius r = 0.200 m. The block of mass m, is allowed to drop, and the cord turns the pulley without slipping. T2 тi т2 (a) Why must the tension T, be greater than the tension T,? This answer has not been graded yet. (b) What is the acceleration of the system, assuming the pulley axis is frictionless? (Give the magnitude of a.) m/s? (c) Find the tensions T, and T2 T2 =
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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Transcribed Image Text:An Atwood's machine consists of blocks of masses m,
= 11.0 kg and m,
= 19.0 kg attached by a cord running over a pulley as in the figure below. The pulley is a solid cylinder with mass M = 9.60 kg and radius r = 0.200 m. The block of mass m,
is
allowed to drop, and the cord turns the pulley without slipping.
T2
тi
т2
(a) Why must the tension T, be greater than the tension T,?
This answer has not been graded yet.
(b) What is the acceleration of the system, assuming the pulley axis is frictionless? (Give the magnitude of a.)
m/s?
(c) Find the tensions T,
and T2
T2 =
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