An astronomical unit (AU) is equal to the average distance from Earth to the Sun, about 92.9 × 106 mi. A parsec (pc) is the distance at which a length of 1 AU would subtend an angle of exactly 1 second of arc (the figure). A light-year (ly) is the distance that light, traveling through a vacuum with a speed of 186000 mi/s, would cover in 1.0 year. Express the Earth-Sun distance in (a) parsecs and (b) light- years. An angle of [ exactly 1 second 1 pc L AU 1 pc (a) Number Units (b) Number i Units

An astronomical unit (AU) is equal to the average distance from Earth to the Sun, about 92.9 × 106 mi. A parsec (pc) is the distance at which a length of 1 AU would subtend an angle of exactly 1 second of arc (the figure). A light-year (ly) is the distance that light, traveling through a vacuum with a speed of 186000 mi/s, would cover in 1.0 year. Express the Earth-Sun distance in (a) parsecs and (b) light- years. An angle of [ exactly 1 second 1 pc L AU 1 pc (a) Number Units (b) Number i Units

University Physics Volume 1

18th Edition

ISBN:9781938168277

Author:William Moebs, Samuel J. Ling, Jeff Sanny

Publisher:William Moebs, Samuel J. Ling, Jeff Sanny

Chapter1: Units And Measurement

Section: Chapter Questions

Problem 55P: The arc length formula says the length sof arc subtended by angle in a circle of radius r is given...

See similar textbooks

Similar questions

Hand written plz asap please fast... Plz fast pzlzzzzz
nework @@ 2 W S Question 9 of 14 X mmand Your answer is partially correct. A person is standing at the edge of the water and looking out at the ocean (see figure). The height of the person's eyes above the water is h= 1.7 m, and the radius of the Earth is R = 6.38 x 106 m. (a) How far is it to the horizon? In other words, what is the distance d from the person's eyes to the horizon? (Note: At the horizon the angle between the line of sight and the radius of the earth is 90°.) (b) Express this distance in miles. (a) Number -0² (b) Number i 2.5 F2 # 3 E D 80 F3 C 3293.33 $ 4 R F Q F4 % 5 V T JAN 20 A 9 F5 Units G Units 6 B mi c F6 Y H & 7 N Horizon K F7 U 8 00 J DII F8 I M ( - O 9 F9 K 1/10 E ⠀ O ) V O D J F10 P 니 - command 4 V P F11 T { + option Ji) E F12 ? 11
What is the number of miles in a light-year, using (see picture) mi/s as the speed of light? I know the number of seconds in a year and 365 days will help but confused on how to put it in the equation.
a method for determining the sizes of the orbits of pl from the sun than Earth. His method involved noting of days between the times that a planet was in the pc A and B in the diagram. Using this time and the num each planet's year, he calculated c and d. a. For Mars, c= 55.2 and d= 103.8. How far is Mars in astronomical units (AU)? One astronomical un the average distance from Earth to the center of th 93 million miles. b. For Jupiter, c 21.9 and d= 100.8. How far is Jup %3D sun in astronomical units? lo olpno er ort to rt .onte eteem-21 o to bre e ne ern 100 o ho aotem t elbl erl pnibioda lert pribiort
How manyy microns make up 1.0km. What fraction of a centimeter equals to 1 micron How many microns arw in 1 yard
The Earth is about 12800 (1.28 x 10^4) in diameter. If you drew the Earth to scale on your model, how many centimeters accross would the dot measure? Show your work if possible please! I attatched a picture of my model! Thanks so much :)
The answer is 11513. Please show me how to get to the answer.
Need help figuring how to do this. I keep getting the wrong answer
A furlong is 220 yd. A fortnight is 2 weeks. Convert a speed of one furlong per fortnight to millimeters per second.
One astronomical unit is about 1.50108 km. Explain why this is the same as 150106 km.
In the Wulff Net, a line with ϕ= 25 and ρ= -45 would be plotted in which quadrant?
Additional Data: VCOM = Vn,LAB/(A + 1) n,COM = A Vn,LAB/(A + 1) VN,COM = - Vn,LAB/(A + 1)