An astronaut stands upright inside a capsule on the moon's surface. What is the difference between the blood pressure at the lower part of his anterior tibial artery and the average blood pressure in his heart, that derives from the height difference of 1.30 m shown in the illustration? Take the density of blood to be 1060 kg/m3 and the acceleration due to gravity on the moon to be 1.62 m/s2. ressure = P, Aorta 1.35 m Anterior tibial artery essure P 8140 N/m2 6360 N/m2 2320 N/m2 2230 N/m2 O 7110 N/m2

College Physics
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Chapter1: Units, Trigonometry. And Vectors
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An astronaut stands upright inside a capsule on the moon's surface. What is the
difference between the blood pressure at the lower part of his anterior tibial artery
and the average blood pressure in his heart, that derives from the height difference of
m shown in the illustration? Take the density of blood to be 1060 kg/m3 and the
1.30
acceleration due to gravity on the moon to be 1.62 m/s2.
2 = రుగంపకి)
Aorta
135m
Anterior
Iblal
artery
essure P,
O8140 N/m2
O6360 N/m
2320 N/m2
2230 N/m2
7110 N/m2
O1.40 x104 N/m2
Transcribed Image Text:An astronaut stands upright inside a capsule on the moon's surface. What is the difference between the blood pressure at the lower part of his anterior tibial artery and the average blood pressure in his heart, that derives from the height difference of m shown in the illustration? Take the density of blood to be 1060 kg/m3 and the 1.30 acceleration due to gravity on the moon to be 1.62 m/s2. 2 = రుగంపకి) Aorta 135m Anterior Iblal artery essure P, O8140 N/m2 O6360 N/m 2320 N/m2 2230 N/m2 7110 N/m2 O1.40 x104 N/m2
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