An astronaut on the moon throws a baseball upward. The astronaut is 6ft 6 in tall. And the velocity of the ball is 50 ft per sec. The height s of the ball in feet is given by the equation s= -2.7t^2 +50t +6.5 where t is the number of seconds after the ball was thrown. After how many seconds is the ball 20 ft above the moons surface?

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