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An astronaut on the moon thro a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 30 ft per sec. The heights of the ball in feet is given by the equation s= -2.71² +30t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 10 ft above the moon's surface? After seconds the ball will be 10 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)

An astronaut on the moon thro a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 30 ft per sec. The heights of the ball in feet is given by the equation s= -2.71² +30t+6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 10 ft above the moon's surface? After seconds the ball will be 10 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.)

Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
Glencoe Algebra 1, Student Edition, 9780079039897, 0079039898, 2018
18th Edition
ISBN:9780079039897
Author:Carter
Publisher:Carter
Chapter9: Quadratic Functions And Equations
Section9.6: Solving Quadratic Equations By Using The Quadratic Formula
Problem 15CYU
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An astronaut on the moon throw's a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 30 ft per sec. The heights of the ball in feet is given by the equation s= -2.71² +30t+ 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 10 ft above the moon's surface? After seconds the ball will be 10 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) @
Transcribed Image Text:An astronaut on the moon throw's a baseball upward. The astronaut is 6 ft, 6 in. tall, and the initial velocity of the ball is 30 ft per sec. The heights of the ball in feet is given by the equation s= -2.71² +30t+ 6.5, where t is the number of seconds after the ball was thrown. Complete parts a and b. a. After how many seconds is the ball 10 ft above the moon's surface? After seconds the ball will be 10 ft above the moon's surface. (Round to the nearest hundredth as needed. Use a comma to separate answers as needed.) @
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