An artist creates a solid sculpture made from 7.60 kg of aluminum. She wishes to create an identical sculpture, using the same mold used to make the original, out of solid silver. What is the mass (in kg) of the silver sculpture? (The density of aluminum is 2.70 x 10 kg/m, and that of silver is 10.50 x 103 kg/m.) kg Need Help? Read It

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Chapter1: Units, Trigonometry. And Vectors
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**Problem Statement:**

An artist creates a solid sculpture made from 7.60 kg of aluminum. She wishes to create an identical sculpture, using the same mold used to make the original, out of solid silver. What is the mass (in kg) of the silver sculpture? 

The densities of the materials are as follows:
- The density of aluminum is \(2.70 \times 10^3 \, \text{kg/m}^3\).
- The density of silver is \(10.50 \times 10^3 \, \text{kg/m}^3\).

**Solution Explanation:**

To solve this problem, you need to understand the relationship between mass, volume, and density. The mass \(m\) of an object is equal to its volume \(V\) multiplied by its density \(\rho\):

\[ m = V \times \rho \]

Since the sculptures are identical in volume:

\[ V_{\text{aluminum}} = V_{\text{silver}} \]

From the mass and density of aluminum, calculate the volume of the aluminum sculpture:

\[ V_{\text{aluminum}} = \frac{m_{\text{aluminum}}}{\rho_{\text{aluminum}}} = \frac{7.60 \, \text{kg}}{2.70 \times 10^3 \, \text{kg/m}^3} \]

Then use the volume to find the mass of the silver sculpture:

\[ m_{\text{silver}} = V_{\text{silver}} \times \rho_{\text{silver}} = V_{\text{aluminum}} \times 10.50 \times 10^3 \, \text{kg/m}^3 \]

By resolving the above equations, you can compute the desired mass of the silver sculpture.
Transcribed Image Text:**Problem Statement:** An artist creates a solid sculpture made from 7.60 kg of aluminum. She wishes to create an identical sculpture, using the same mold used to make the original, out of solid silver. What is the mass (in kg) of the silver sculpture? The densities of the materials are as follows: - The density of aluminum is \(2.70 \times 10^3 \, \text{kg/m}^3\). - The density of silver is \(10.50 \times 10^3 \, \text{kg/m}^3\). **Solution Explanation:** To solve this problem, you need to understand the relationship between mass, volume, and density. The mass \(m\) of an object is equal to its volume \(V\) multiplied by its density \(\rho\): \[ m = V \times \rho \] Since the sculptures are identical in volume: \[ V_{\text{aluminum}} = V_{\text{silver}} \] From the mass and density of aluminum, calculate the volume of the aluminum sculpture: \[ V_{\text{aluminum}} = \frac{m_{\text{aluminum}}}{\rho_{\text{aluminum}}} = \frac{7.60 \, \text{kg}}{2.70 \times 10^3 \, \text{kg/m}^3} \] Then use the volume to find the mass of the silver sculpture: \[ m_{\text{silver}} = V_{\text{silver}} \times \rho_{\text{silver}} = V_{\text{aluminum}} \times 10.50 \times 10^3 \, \text{kg/m}^3 \] By resolving the above equations, you can compute the desired mass of the silver sculpture.
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