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An artificial satellite moves in a circular orbit at a heighth 2.89 x 105 m above the Earth's surface, a location where the acceleration (centripetal) due to gravity is 9.00 m/s?. The Earth's radius is 6.38 x 106 m. What is the orbital period 'T' of the satellite at this location? {Consider the altitude and the Earth's radius} O 5,790 s O 5,410 s O 1,030 s O 4,920 s O 6,820 s

An artificial satellite moves in a circular orbit at a heighth 2.89 x 105 m above the Earth's surface, a location where the acceleration (centripetal) due to gravity is 9.00 m/s?. The Earth's radius is 6.38 x 106 m. What is the orbital period 'T' of the satellite at this location? {Consider the altitude and the Earth's radius} O 5,790 s O 5,410 s O 1,030 s O 4,920 s O 6,820 s

College Physics
College Physics
11th Edition
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Raymond A. Serway, Chris Vuille
Chapter1: Units, Trigonometry. And Vectors
Section: Chapter Questions
Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...
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### Orbital Period of a Satellite An artificial satellite moves in a circular orbit at a height \( h = 2.89 \times 10^5 \, \text{m} \) above the Earth's surface, at a location where the acceleration (centripetal) due to gravity is \( 9.00 \, \text{m/s}^2 \). The Earth's radius is \( 6.38 \times 10^6 \, \text{m} \). What is the orbital period 'T' of the satellite at this location? (Consider the altitude and the Earth's radius.) **Options:** - \( 5,790 \, \text{s} \) - \( 5,410 \, \text{s} \) - \( 1,030 \, \text{s} \) - \( 4,920 \, \text{s} \) - \( 6,820 \, \text{s} \) #### Explanation: The image provided includes a photograph of a satellite orbiting Earth, offering a visual context of the scenario described in the question. The main goal is to calculate the orbital period 'T' using the given parameters and the formula for circular orbital motion.
Transcribed Image Text:### Orbital Period of a Satellite An artificial satellite moves in a circular orbit at a height \( h = 2.89 \times 10^5 \, \text{m} \) above the Earth's surface, at a location where the acceleration (centripetal) due to gravity is \( 9.00 \, \text{m/s}^2 \). The Earth's radius is \( 6.38 \times 10^6 \, \text{m} \). What is the orbital period 'T' of the satellite at this location? (Consider the altitude and the Earth's radius.) **Options:** - \( 5,790 \, \text{s} \) - \( 5,410 \, \text{s} \) - \( 1,030 \, \text{s} \) - \( 4,920 \, \text{s} \) - \( 6,820 \, \text{s} \) #### Explanation: The image provided includes a photograph of a satellite orbiting Earth, offering a visual context of the scenario described in the question. The main goal is to calculate the orbital period 'T' using the given parameters and the formula for circular orbital motion.
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