An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with u = 44 and o = 5.5. A USE SALT (a) What is the probability that yield strength is at most 387 Greater than 66? (Round your answers to four decimal places.) at most 38 0.2336 greater than 66 (b) What yield strength value separates the strongest 75% from the others? (Round your answer to four decimal places.) 0.0001 |× ksi

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**Transcription for Educational Website:**

An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with \( \mu = 44 \) and \( \sigma = 5.5 \).

**(a)** What is the probability that yield strength is at most 38? Greater than 66? (Round your answers to four decimal places.)

- at most 38: **0.2336**
- greater than 66: **[Input Required]**

**(b)** What yield strength value separates the strongest 75% from the others? (Round your answer to four decimal places.)

- **0.0001 ksi**

You may need to use the appropriate table in the [Appendix of Tables](#) to answer this question.

**Explanation:**

This section illustrates a problem regarding the probability distribution of yield strength for A36 grade steel. The mean (\( \mu \)) is 44, and the standard deviation (\( \sigma \)) is 5.5, indicating the data follows a normal distribution. It includes probability calculations for specific values and a critical value determination separating the top 75% from the rest.
Transcribed Image Text:**Transcription for Educational Website:** An article suggested that yield strength (ksi) for A36 grade steel is normally distributed with \( \mu = 44 \) and \( \sigma = 5.5 \). **(a)** What is the probability that yield strength is at most 38? Greater than 66? (Round your answers to four decimal places.) - at most 38: **0.2336** - greater than 66: **[Input Required]** **(b)** What yield strength value separates the strongest 75% from the others? (Round your answer to four decimal places.) - **0.0001 ksi** You may need to use the appropriate table in the [Appendix of Tables](#) to answer this question. **Explanation:** This section illustrates a problem regarding the probability distribution of yield strength for A36 grade steel. The mean (\( \mu \)) is 44, and the standard deviation (\( \sigma \)) is 5.5, indicating the data follows a normal distribution. It includes probability calculations for specific values and a critical value determination separating the top 75% from the rest.
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