An article reports that 1 in 500 people carry the defective gene that causes inherited colon cancer. In a sample of 2500 individuals,what is the approximate distribution of the number who carry this gene?We can approximate this distribution by the Poisson distribution with μ = 5(a) Use the Poisson approximation to calculate the approximate probability that between 6 and 11 (inclusive) carry the gene.(Round your answer to three decimal places.)0.214X(b) Use the Poisson approximation to calculate the approximate probability that at least 11 carry the gene. (Round your answer tothree decimal places.)0.0028xYou may need to use the appropriate table in the Appendix of Tables to answer this question.

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Answered: An article reports that 1 in 500 people…

A First Course in Probability (10th Edition)

10th Edition

ISBN:9780134753119

Author:Sheldon Ross

Publisher:Sheldon Ross

Chapter1: Combinatorial Analysis

Section: Chapter Questions

Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...

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Rosie is an aging sheepdog in Montana who gets regular checkups from her owner, the local veterinarian. Let x be a random variable that represents Rosie’s resting heart rate (in beats per minute). From past experience, the vet knows that x has a normal distribution with σ= 12. The vet checked the manual and found that for dogs of this breed, μ= 115beats per minute. Over the past six weeks(n=6), Rosie’s sample mean hear rate was x̄=105.0. The vet is concerned that Rosie’s heart rate is slowing and is less than 115.0. Does the data indicate that this is the case? Use a level of significance α= .05 to conduct a hypothesis test. You must include the following: i) null hypothesis ii) alternate hypothesis iii) test statistic (z or t value –remember the information in the problem will help determine if you use a z or t) iv) P-Value compared to the level of significance(α). v) Conclusion (Do you reject or fail to reject the vet’s claim?)
Check in each case whether the normal approxima-tion to the binomial distribution may be used according to the rule of thumb in Section 6.(a) n = 16 and θ = 0.20;(b) n = 65 and θ = 0.10;(c) n = 120 and θ = 0.98.
F(144) Generation Y has been defined as those individuals who were born between 1981 and 1991. A 2010 survey by a credit counseling foundation found that 60% of the young adults in Generation Y pay their monthly bills on time. Suppose we take a random sample of 190 people from Generation Y. Question content area bottom Part 1 The distribution of p is a aproximately normal. Calculate the standard deviaiton of p. σp=enter your response here (Round to four decimal places as needed.) What is the probability that between 106 and 120 of them will pay their monthly bills on time? P(Between 106 and 120 of them will pay their monthly bills on time)=enter your response here (Round to four decimal places as needed.)
A Poisson distribution with λ =7.4 λ =7.4 and x=5Use the probability distribution identified above to calculate the following:
Assume that the probability of a being born with Genetic Condition B is p = 7/60. A study looks at a random sample of 826 volunteers. Find the most likely number of the 826 volunteers to have Genetic Condition B. (Round answer to one decimal place.) H = Let X represent the number of volunteers (out of 826) who have Genetic Condition B. Find the standard deviation for the probability distribution of X. (Round answer to two ecimal places.) 0 = Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+2o. Enter answer as an interval using square-brackets only with whole numbers. usual values =
Assume that the probability of a being born with Genetic Condition B is p = 11/60. A study looks at a random sample of 1384 volunteers. Find the most likely number of the 1384 volunteers to have Genetic Condition B. (Round answer to one decimal place.) μ = Let X represent the number of volunteers (out of 1384) who have Genetic Condition B. Find the standard deviation for the probability distribution of X. (Round answer to two decimal places.) 0 = Use the range rule of thumb to find the minimum usual value µ-20 and the maximum usual value μ+20. Enter answer as an interval using square-brackets only with whole numbers. usual values=
The cumulative probability of a Chi-Square distribution runs left to right. 0 is on the left, and 1 is on the right. True False
The random variable xx represents the number of emails received at a help desk in one hour, and it has a Poisson distribution with a mean of 7.9. (Round to two decimal places.)What is the variance?σ2 = What is the standard deviation?σ =
Assume that the probability of a being born with Genetic Condition B is π=π=14/15. A study looks at a random sample of 173 volunteers.Find the most likely number of the 173 volunteers to have Genetic Condition B. (Round answer to one decimal place.) μ = Let XX represent the number of volunteers (out of 173) who have Genetic Condition B. Find the standard deviation for the probability distribution of XX. (Round answer to two decimal places.) σ = Use the range rule of thumb to find the minimum usual value μ-2σ and the maximum usual value μ+2σ.Enter answer as an interval using square-brackets only with whole numbers. ? Round your answer to one decimal place.usual values =
A technician suspect that the number of computer errors recorded per day in the LAN follows a Poisson distribution with a mean of 2 errors per day. Record of the number of errors per day for the past 260 days are shown in table below. Number of Number of Pr(X = x) E (0; – e;) Errors per days ei day 77 1 90 2 55 3 30 4 or more a. Test the hypothesis that the number of computer errors per day has the Poisson distribution with mean 2 at the 5% significance level. b. Find an approximate value of the p – value for the test statistics in (a). 8
Please help with parts a and b
The mean percent of childhood asthma prevalence in 43 cities is 2.21%. A random sample of 32 of these cities is selected. What is the probability that the mean childhood asthma prevalence for the sample is greater than 2.6%? Interpret this probability. Assume that o= = 1.21%. The probability is (Round to four decimal places as needed.)

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