An article reported the results of a peer tutoring program to help children learn to read. In the experiment, Form 2 of the Gates-MacGintie Reading Test was administered to both an experimental group and a control group after 6 weeks of instruction, during which the experimental group received peer tutoring and the control group did not. For the experimental group n1 = 30 children, the mean score on the vocabulary portion of the test was x1 = 368.4, with sample standard deviation s1 = 39.3. The average score on the vocabulary portion of the test for the n2 = 30 subjects in the control group was x2 = 349.2 with sample standard deviation s2 = 56.8. Use a 1% level of significance to test the claim that the experimental group performed better than the control group. What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)
Inverse Normal Distribution
The method used for finding the corresponding z-critical value in a normal distribution using the known probability is said to be an inverse normal distribution. The inverse normal distribution is a continuous probability distribution with a family of two parameters.
Mean, Median, Mode
It is a descriptive summary of a data set. It can be defined by using some of the measures. The central tendencies do not provide information regarding individual data from the dataset. However, they give a summary of the data set. The central tendency or measure of central tendency is a central or typical value for a probability distribution.
Z-Scores
A z-score is a unit of measurement used in statistics to describe the position of a raw score in terms of its distance from the mean, measured with reference to standard deviation from the mean. Z-scores are useful in statistics because they allow comparison between two scores that belong to different normal distributions.
An article reported the results of a peer tutoring program to help children learn to read. In the experiment, Form 2 of the Gates-MacGintie Reading Test was administered to both an experimental group and a control group after 6 weeks of instruction, during which the experimental group received peer tutoring and the control group did not. For the experimental group n1 = 30 children, the mean score on the vocabulary portion of the test was x1 = 368.4, with sample standard deviation s1 = 39.3. The average score on the vocabulary portion of the test for the n2 = 30 subjects in the control group was x2 = 349.2 with sample standard deviation s2 = 56.8. Use a 1% level of significance to test the claim that the experimental group performed better than the control group.
What is the value of the sample test statistic? (Test the difference μ1 − μ2. Round your answer to three decimal places.)
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