An article in Nature Genetics studied gene expression as a function of treatments for leukemia. One group received a high dose of the drug, while the control group received no treatment. Expression data (measures of gene activity) from one gene were measured for each group of patients and presented in the box plot. Which statement describes the best interpretation of data based on the box plot? Boxplot of High Dose, Control, Control_1, Control_2 3000 2500 - 2000 - 1500 - 1000 - 500- 0- High Dose Control Control_1 Control_2 a. Further data is needed for patients that received no treatment especially that variances differ as shown in control group 2 O b. Patients under control group 2 has the highest mean and greatest dispersion O. All distribution are centered at about the same value but it's apparent that variances differ O d. Those patients receiving high dose of the drug has the lowest measurement of gene activity Data ***
An article in Nature Genetics studied gene expression as a function of treatments for leukemia. One group received a high dose of the drug, while the control group received no treatment. Expression data (measures of gene activity) from one gene were measured for each group of patients and presented in the box plot. Which statement describes the best interpretation of data based on the box plot? Boxplot of High Dose, Control, Control_1, Control_2 3000 2500 - 2000 - 1500 - 1000 - 500- 0- High Dose Control Control_1 Control_2 a. Further data is needed for patients that received no treatment especially that variances differ as shown in control group 2 O b. Patients under control group 2 has the highest mean and greatest dispersion O. All distribution are centered at about the same value but it's apparent that variances differ O d. Those patients receiving high dose of the drug has the lowest measurement of gene activity Data ***
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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