An article in the Electronic Components and Technology Conference (Vol. 52, 2001, pp. 1167–1171) describes a study comparing single versus dual spindle saw processes on copper metallized wafers. A total of \( n_{\text{single}} = 10 \) devices of the single saw type and a total of \( n_{\text{double}} = 12 \) devices of the double saw type were measured for the width of the backside chipouts. The sample mean chipouts for the single saw type were \( \bar{x}_{\text{single}} = 68.9 \) with a sample standard deviation of \( s_{\text{single}} = 7.3 \). The sample mean chipouts for the double saw type were \( \bar{x}_{\text{double}} = 49.0 \) with a sample standard deviation of \( s_{\text{double}} = 8.7 \).**Assume that both populations are normally distributed and have the same variance.** Calculate the upper bound of a 95% two-sided confidence interval on the mean difference in spindle saw process where the difference is "single - double". Enter your answer to two decimal places.**Hint:** The formula for a confidence interval using the pooled variance (assumes equal variances) is \[(\bar{x}_1 - \bar{x}_2) \pm t_{\alpha/2, n_1 + n_2 - 2} \times s_p \times \sqrt{\frac{1}{n_1} + \frac{1}{n_2}}\]

The single saw type has the sample size 10, sample mean 68.9, and sample standard deviation 7.3. The…

Answered: An article in Electronic Components and…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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If you perform FFT on 20 seconds of data with no averaging, what are the first 3 values of the corresponding frequency vector in Hz?
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