An article in American Demographics claims that more than twice as many shoppers are out shopping on the weekends thanduring the week. Not only that, such shoppers also spend more money on their purchases on Saturdays and Sundays!Suppose that the amount of money spent at shopping centers between 4 p.m. and 6 p.m. on Sundays has a normaldistribution with mean $180 and with a standard deviation of $20. A shopper is randomly selected on a Sunday between4 p.m. and 6 p.m. and asked about his spending patterns.In USE SALT(a) What is the probability that he has spent more than $190 at the mall? (Round your answer to four decimal places.)(b) What is the probability that he has spent between $190 and $205 at the mall? (Round your answer to four decimalplaces.)(c) If two shoppers are randomly selected, what is the probability that both shoppers have spent more than $205 at themall? (Round your answer to four decimal places.)You may need to use the appropriate appendix table to answer this question.

Let X be the random variable from normal distribution with mean (μ) = $180 and standard deviation…

Answered: An article in American Demographics…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Solar energy is considered by many to be the energy of the future. A recent survey was taken to compare the cost of solar energy to the cost of gas or electric energy. Results of the survey revealed that the distribution of the amount of the monthly utility bill of a three-bedroom house using gas or electric energy had a mean of $117 and a standard deviation of $13. If the distribution can be considered normal: Approximately what percentage of homes will have a monthly utility bill less than $78? Note: Do NOT include the "%" sign Do NOT round any decimals, if applicable
Is it worth pursuing a doctoral degree in education if you already have an undergraduate degree? One way to help make this decision is to look at the mean incomes of these two groups. Suppose that 15 people with bachelor’s degrees in education were surveyed. Their mean annual salary was $⁢31,500 with a standard deviation of $⁢7900. Seventeen people with doctoral degrees in education were found to have a mean annual salary of $⁢47,500 with a standard deviation of $⁢6900. Assume that the population variances are not the same. Construct a 99% confidence interval to estimate the true difference between the mean salaries for people with doctoral degrees and undergraduate degrees in education. Let Population 1 be the salaries for people with doctoral degrees and Population 2 be the salaries for people with undergraduate degrees. Round the endpoints of the interval to the nearest whole number, if necessary.
It is known that incomes from the USA follow a normal distribution with a mean of $55,000 and a standard deviation of $12,000. A researcher took a sample of 100 people in the USA and obtained a sample mean of $67,000 with a standard deviation of $18,000. What are the characteristics of the sampling distribution. A. Mean = $55,000 and Standard Deviation of the Mean = $1200 B. Mean = $55,000 and Standard Deviation of the Mean = $12000 C. Mean = $67,000 and Standard Deviation of the Mean = $569.21 D. Mean = $67,000 and Standard Deviation of the Mean = $1800
A marketing consultant is hired by a major restaurant chain wishing to investigate the preferences and spending patterns of lunch customers. The CEO of the chain hypothesized that the average customer spends at least $13.50 on lunch. A survey of 25 customers sampled at one of the restaurants found the average lunch bill per customer to be ?¯=$14.50 . Based on previous surveys, the restaurant informs the marketing manager that the standard deviation is ?=$3.50 . To address the CEO’s conjecture, the marketing manager carried out a hypothesis test of ?0:?=13.50 vs. ??:?>13.50 and obtained a ?‑value = 0.77. The marketing chooses a significance level of ?=0.10. If he uses this significance level throughout his work, how often will he reject a true null hypothesis? Group of answer choices a.He will reject 10% of all true null hypotheses. b. He will reject 1% of all true null hypotheses. c. He will reject 5% of all true null hypotheses. d. He will not reject 10% of all true null…
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An article in American Demographics claims that more than twice as many shoppers are out shopping on the weekends than during the week. Not only that, such shoppers also spend more money on their purchases on Saturdays and Sundays! Suppose that the amount of money spent at shopping centers between 4 p.m. and 6 p.m. on Sundays has a normal distribution with mean $195 and with a standard deviation of $20. A shopper is randomly selected on a Sunday between 4 p.m. and 6 p.m. and asked about his spending patterns. What is the probability that he has spent between $205 and $225 at the mall? (Round your answer to four decimal places.)
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According to Kaiser Family Foundation survey in 2011 and 2010, the average premium for employer-sponsored health insurance for family coverage was $15,073 in 2011 and $13,770 in 2010 (USA TODAY, September 29, 2011). Suppose that these averages were based on random samples of 250 and 200 employees who had such employer-sponsored health insurance plans for 2011 and 2010, respectively. Further assume that the population standard deviations for 2011 and 2010 were $2160 and $1990, respectively.

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