An arrow is shot upward, with an initial velocity of 90 meters per second, at an angle of 34° with respect to the horizontal. The arrow is shot from a height of 6 meters above the ground. The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric equations below. = (v₁ cose)t y=−4.9t²+(v sin0)t+h X Here vo is the initial velocity, is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions.

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A: Introduction:

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