An arrow is shot upward, with an initial velocity of 80 meters per second, at an angle of 52° with respect to the horizontal. The arrow is shot from a height of 9 meters above the ground. The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric equations below. y=-4.9? + (v, sin 0)r +h Here v is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the arrow reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. seconds (b) What is the maximum height of the arrow? Round your answer to the nearest tenth. I meters

Algebra and Trigonometry (6th Edition)
6th Edition
ISBN:9780134463216
Author:Robert F. Blitzer
Publisher:Robert F. Blitzer
ChapterP: Prerequisites: Fundamental Concepts Of Algebra
Section: Chapter Questions
Problem 1MCCP: In Exercises 1-25, simplify the given expression or perform the indicated operation (and simplify,...
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An arrow is shot upward, with an initial velocity of 80 meters per second, at an angle of 52° with respect to the horizontal. The arrow is shot from a height of9
meters above the ground.
The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric equations
below.
cos
y=-4.9r + (vo sin e)r +h
Here vo
is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height.
Use the equations to answer the following questions.
(a) When does the arrow reach its maximum height?
Do not round any intermediate computations. Round your answer to
the nearest hundredth.
seconds
(b) What is the maximum height of the arrow?
Round your answer to the nearest tenth.
meters
RP
Transcribed Image Text:An arrow is shot upward, with an initial velocity of 80 meters per second, at an angle of 52° with respect to the horizontal. The arrow is shot from a height of9 meters above the ground. The horizontal distance x from the starting point and the height y above the ground of the arrow t seconds after it is shot are given by the parametric equations below. cos y=-4.9r + (vo sin e)r +h Here vo is the initial velocity, 0 is the initial angle with respect to the horizontal, and h is the initial height. Use the equations to answer the following questions. (a) When does the arrow reach its maximum height? Do not round any intermediate computations. Round your answer to the nearest hundredth. seconds (b) What is the maximum height of the arrow? Round your answer to the nearest tenth. meters RP
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