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An arrow is shot into the air so that its horizontal velocity is 37.0 ft/sec and it vertical velocity is 11.0 ft/sec respectively. Find the velocity of the arrow. Round your answer to the nearest ft/sec. 39 feet per second 27 feet per second 35 feet per second 24 feet per second

An arrow is shot into the air so that its horizontal velocity is 37.0 ft/sec and it vertical velocity is 11.0 ft/sec respectively. Find the velocity of the arrow. Round your answer to the nearest ft/sec. 39 feet per second 27 feet per second 35 feet per second 24 feet per second

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter10: Measurement, Area, And Volume
Section10.8: Volumes Of Pyramids And Cones
Problem 12E
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### Projectile Motion Problem **Problem Statement:** An arrow is shot into the air so that its horizontal velocity is 37.0 ft/sec and its vertical velocity is 11.0 ft/sec respectively. Find the velocity of the arrow. Round your answer to the nearest ft/sec. ### Multiple Choice Answers: - 39 feet per second - 27 feet per second - 35 feet per second - 24 feet per second ### Solution Explanation: To find the velocity of the arrow, we need to calculate the resultant velocity using the Pythagorean theorem. Given: - Horizontal velocity (\(V_x\)) = 37.0 ft/sec - Vertical velocity (\(V_y\)) = 11.0 ft/sec The resultant velocity (\(V_r\)) can be found using the formula: \[ V_r = \sqrt{V_x^2 + V_y^2} \] Plugging in the values: \[ V_r = \sqrt{(37.0)^2 + (11.0)^2} \] \[ V_r = \sqrt{1369 + 121} \] \[ V_r = \sqrt{1490} \] \[ V_r \approx 38.6 \] Rounding to the nearest ft/sec, the resultant velocity is: \[ V_r \approx 39 \text{ feet per second} \] Thus, the correct answer is **39 feet per second**.
Transcribed Image Text:### Projectile Motion Problem **Problem Statement:** An arrow is shot into the air so that its horizontal velocity is 37.0 ft/sec and its vertical velocity is 11.0 ft/sec respectively. Find the velocity of the arrow. Round your answer to the nearest ft/sec. ### Multiple Choice Answers: - 39 feet per second - 27 feet per second - 35 feet per second - 24 feet per second ### Solution Explanation: To find the velocity of the arrow, we need to calculate the resultant velocity using the Pythagorean theorem. Given: - Horizontal velocity (\(V_x\)) = 37.0 ft/sec - Vertical velocity (\(V_y\)) = 11.0 ft/sec The resultant velocity (\(V_r\)) can be found using the formula: \[ V_r = \sqrt{V_x^2 + V_y^2} \] Plugging in the values: \[ V_r = \sqrt{(37.0)^2 + (11.0)^2} \] \[ V_r = \sqrt{1369 + 121} \] \[ V_r = \sqrt{1490} \] \[ V_r \approx 38.6 \] Rounding to the nearest ft/sec, the resultant velocity is: \[ V_r \approx 39 \text{ feet per second} \] Thus, the correct answer is **39 feet per second**.
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