An arithmetic sequence has first term a=5 and common difference d=4. How many terms of this sequence must be added to get 2849 terms? I know the answer is 37 but I don't understand how to get it? I end up with 5698 =6n + 4n2 I understand I would need to divide 4 from 4n2 but then I get a fraction that doesn't factor nicely? Can you please explain the steps I am missing in detail.
An arithmetic sequence has first term a=5 and common difference d=4. How many terms of this sequence must be added to get 2849 terms? I know the answer is 37 but I don't understand how to get it? I end up with 5698 =6n + 4n2 I understand I would need to divide 4 from 4n2 but then I get a fraction that doesn't factor nicely? Can you please explain the steps I am missing in detail.
Calculus: Early Transcendentals
8th Edition
ISBN:9781285741550
Author:James Stewart
Publisher:James Stewart
Chapter1: Functions And Models
Section: Chapter Questions
Problem 1RCC: (a) What is a function? What are its domain and range? (b) What is the graph of a function? (c) How...
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An arithmetic sequence has first term a=5 and common difference d=4. How many terms of this sequence must be added to get 2849 terms?
I know the answer is 37 but I don't understand how to get it?
I end up with 5698 =6n + 4n2
I understand I would need to divide 4 from 4n2
but then I get a fraction that doesn't factor nicely? Can you please explain the steps I am missing in detail.
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