An aqueous solution of glycine (Mr = 75.1 g/mol) has a molality of 1.50 mol/Kg Calculate molarity of this solution and the mole fraction of glycine in the solution. Assume density of the solution to be 1.00 g/cm³. Mal fraction = 1500,0 1909 √= (1.50 x1000) X 751 Now, M = mol Volume = 1·50x1000 -
An aqueous solution of glycine (Mr = 75.1 g/mol) has a molality of 1.50 mol/Kg Calculate molarity of this solution and the mole fraction of glycine in the solution. Assume density of the solution to be 1.00 g/cm³. Mal fraction = 1500,0 1909 √= (1.50 x1000) X 751 Now, M = mol Volume = 1·50x1000 -
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An aqueous solution of glycine (Mr = 75.1 g/mol) has a molality of 1.50 mol/Kg Calculate
molarity of this solution and the mole fraction of glycine in the solution. Assume density of the
solution to be 1.00 g/cm³.
Mal fraction = 1500,0
√= (1.50×1000) X 75-1
= 19019
78.
Now, M = moj
Volume
=1.50×1000](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F67214770-ee3a-4ed8-9630-52c9b6a47b38%2Feb61851d-b35a-458d-aeec-b297c7fee312%2Fgqvfglj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:dl
An aqueous solution of glycine (Mr = 75.1 g/mol) has a molality of 1.50 mol/Kg Calculate
molarity of this solution and the mole fraction of glycine in the solution. Assume density of the
solution to be 1.00 g/cm³.
Mal fraction = 1500,0
√= (1.50×1000) X 75-1
= 19019
78.
Now, M = moj
Volume
=1.50×1000
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