An aqueous solution of 2 percent non-volatile solute exerts a pressure of 1.004 bar at the boiling point of the solvent. What is the molecular mass of the solute?[Vapour pressure of water = 1.013 bar]

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An aqueous solution of 2 percent non-volatile solute exerts a pressure of 1.004 bar at the boiling point of the solvent. What is the molecular mass of the solute?
[Vapour pressure of water = 1.013 bar] 

Expert Solution
Step 1

Given,

Vapor pressure of water = 1.013 barVapor pressure of solutions = 1.004 barPercentage of solute = 2 %

To find -

The molar mass of the solute

Step 2

According to Raoult's Law,

(p1° - p1)p1°  =  (w2 × M1 )(M2  × w1 )where, p1° = vapor pressure pure solventp1 = vapor pressure of solutionw2 = Mass of solutew1 = mass of solventM1 = molar mass of solventM2 = molar mass of solute

Step 3

Here,

Assume- 

Mass of solute to be 2 gThen,Mass of solvent = (100-2) g = 98 g

Thus,

(p1° - p1)p1°  =  (w2 × M1 )(M2  × w1 )      ........................................(1)where, p1° = vapor pressure pure solvent i.e water = 1.013 barp1 = vapor pressure of solution = 1.004 barw2 = Mass of solute = 2 gw1 = mass of solvent = 98 gM1 = molar mass of solvent i.e water =18 g mol-1M2 = molar mass of solute to be calculated 

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