An aqueous potassium hydroxide (KOH) solution is 14.65% KOH by mass and has a density of 1.10 g/mL. Assume there is 100 g of solution. KOH 56.91 g/mol. (a) What is the molarity (M) of the KOH solution? (b) What is the molality (m) of the KOH solution? The answer to part (a) is 2.83 M. The answer to part (b) is 3.02 m. Could someone please show me the steps to get these answers?

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An aqueous potassium
hydroxide (KOH) solution is
14.65% KOH by mass and has a
density of 1.10 g/mL. Assume
there is 100 g of solution. KOH
= 56.91 g/mol. (a) What is the
molarity (M) of the KOH
solution? (b) What is the molality
(m) of the KOH solution? The
answer to part (a) is 2.83 M. The
answer to part (b) is 3.02 m.
Could someone please show me
the steps to get these answers?
Transcribed Image Text:An aqueous potassium hydroxide (KOH) solution is 14.65% KOH by mass and has a density of 1.10 g/mL. Assume there is 100 g of solution. KOH = 56.91 g/mol. (a) What is the molarity (M) of the KOH solution? (b) What is the molality (m) of the KOH solution? The answer to part (a) is 2.83 M. The answer to part (b) is 3.02 m. Could someone please show me the steps to get these answers?
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