An application of Kirchhoff's Rules to the circuit shown results in the following system of equations. Find the currents 1₁, 12, 13. 12 = 1₁ +13 5-41₁-512 = 0 10 - 512 - 713 = 0 Select the correct choice below and fill in any answer boxes in your choice. OA. The currents are ₁ = 1₂ = ₁ and 13 = (Type integers or fractions.) OB. There are infinitely many solutions. OC. There is no solution. 792 13 21355 Ω 10 V 4 Ω 5 V
An application of Kirchhoff's Rules to the circuit shown results in the following system of equations. Find the currents 1₁, 12, 13. 12 = 1₁ +13 5-41₁-512 = 0 10 - 512 - 713 = 0 Select the correct choice below and fill in any answer boxes in your choice. OA. The currents are ₁ = 1₂ = ₁ and 13 = (Type integers or fractions.) OB. There are infinitely many solutions. OC. There is no solution. 792 13 21355 Ω 10 V 4 Ω 5 V
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Chapter1: Units, Trigonometry. And Vectors
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![### Application of Kirchhoff's Rules
An application of Kirchhoff's Rules to the circuit shown results in the following system of equations. Find the currents \( I_1 \), \( I_2 \), \( I_3 \):
\[
\begin{cases}
I_2 = I_1 + I_3 \\
5 - 4I_1 - 5I_2 = 0 \\
10 - 5I_2 - 7I_3 = 0
\end{cases}
\]
**Diagram Explanation:**
The diagram depicts a circuit comprising the following components:
1. Three resistors with resistances of 7Ω, 5Ω, and 4Ω.
2. Two voltage sources of 10V and 5V.
3. Three currents \( I_1 \), \( I_2 \), and \( I_3 \), flowing in different parts of the circuit. \( I_1 \) flows through the 5Ω and 4Ω resistors, \( I_2 \) passes through the 7Ω and 5Ω resistors, and \( I_3 \) flows through the 7Ω resistor.
The direction of \( I_1 \) is shown as flowing to the right, \( I_2 \) is flowing upwards, and \( I_3 \) is flowing to the left.
---
### Question:
Select the correct choice below and fill in any answer boxes in your choice.
**Options:**
- **A.** The currents are \( I_1 = \_\_\_ \), \( I_2 = \_\_\_ \), and \( I_3 = \_\_\_ \). (Type integers or fractions.)
- **B.** There are infinitely many solutions.
- **C.** There is no solution.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F349eaa27-36eb-4309-87e3-9ff3181a3e80%2F0512c1c9-7edc-4fe3-936b-7d8167da2d93%2Fu6awqnj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:### Application of Kirchhoff's Rules
An application of Kirchhoff's Rules to the circuit shown results in the following system of equations. Find the currents \( I_1 \), \( I_2 \), \( I_3 \):
\[
\begin{cases}
I_2 = I_1 + I_3 \\
5 - 4I_1 - 5I_2 = 0 \\
10 - 5I_2 - 7I_3 = 0
\end{cases}
\]
**Diagram Explanation:**
The diagram depicts a circuit comprising the following components:
1. Three resistors with resistances of 7Ω, 5Ω, and 4Ω.
2. Two voltage sources of 10V and 5V.
3. Three currents \( I_1 \), \( I_2 \), and \( I_3 \), flowing in different parts of the circuit. \( I_1 \) flows through the 5Ω and 4Ω resistors, \( I_2 \) passes through the 7Ω and 5Ω resistors, and \( I_3 \) flows through the 7Ω resistor.
The direction of \( I_1 \) is shown as flowing to the right, \( I_2 \) is flowing upwards, and \( I_3 \) is flowing to the left.
---
### Question:
Select the correct choice below and fill in any answer boxes in your choice.
**Options:**
- **A.** The currents are \( I_1 = \_\_\_ \), \( I_2 = \_\_\_ \), and \( I_3 = \_\_\_ \). (Type integers or fractions.)
- **B.** There are infinitely many solutions.
- **C.** There is no solution.
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