An application of Kirchhoff's Rules to the 4 +8- 212 = 0 6 2 circuit shown results in the following system of equations. 8 = 814 +11 12 222 4 = 613 +11 I3 + l4 = 11 Find the currents I,. 12. 13. 14- Select the correct choice below and fill in any answer boxes within your choice. O A. The currents are l, = 13 = and l4 = (Simplify your answers.) B. There is no possible combination of currents that satisfy the circuit. a a
An application of Kirchhoff's Rules to the 4 +8- 212 = 0 6 2 circuit shown results in the following system of equations. 8 = 814 +11 12 222 4 = 613 +11 I3 + l4 = 11 Find the currents I,. 12. 13. 14- Select the correct choice below and fill in any answer boxes within your choice. O A. The currents are l, = 13 = and l4 = (Simplify your answers.) B. There is no possible combination of currents that satisfy the circuit. a a
College Physics
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Author:Raymond A. Serway, Chris Vuille
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Chapter1: Units, Trigonometry. And Vectors
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![- 4 +8- 212 = 0
An application of Kirchhoffs Rules to the
circuit shown results in the following
system of equations.
6 2
4 V
8 = 814 +11
12
Find the currents I,, 12. 13. 14.
4 = 613 +1
%31
13 + l4 = 1
Select the correct choice below and fill in any answer boxes within your choice.
O A. The currents are l, =
13
and I4 =
(Simplify your answers.)
B. There is no possible combination of currents that satisfy the circuit.](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F6e8767a2-9999-4bb8-a4cf-9b4c9a877720%2Fc3020814-04b0-4d5e-9fbf-a4ed1a673e47%2Foac57lm_processed.png&w=3840&q=75)
Transcribed Image Text:- 4 +8- 212 = 0
An application of Kirchhoffs Rules to the
circuit shown results in the following
system of equations.
6 2
4 V
8 = 814 +11
12
Find the currents I,, 12. 13. 14.
4 = 613 +1
%31
13 + l4 = 1
Select the correct choice below and fill in any answer boxes within your choice.
O A. The currents are l, =
13
and I4 =
(Simplify your answers.)
B. There is no possible combination of currents that satisfy the circuit.
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