An ant starts at the point (0,0), and walks either one unit up, or one unit to the right, until it reaches the point (5,4). How many possible paths can the ant take?
An ant starts at the point (0,0), and walks either one unit up, or one unit to the right, until it reaches the point (5,4). How many possible paths can the ant take?
Advanced Engineering Mathematics
10th Edition
ISBN:9780470458365
Author:Erwin Kreyszig
Publisher:Erwin Kreyszig
Chapter2: Second-order Linear Odes
Section: Chapter Questions
Problem 1RQ
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![**Problem 5:** An ant starts at the point (0, 0) and walks either one unit up, or one unit to the right, until it reaches the point (5, 4). How many possible paths can the ant take?
**Solution Explanation:**
To solve this problem, we can think of the ant's movement as a sequence of steps: the ant needs to make a total of 5 right moves and 4 up moves to reach the desired point. The order in which these moves are made determines the path.
The problem is equivalent to finding the number of ways to arrange a sequence of 5 "R" (right) moves and 4 "U" (up) moves. This is a combinatorial problem that can be solved using binomial coefficients.
The number of possible sequences can be calculated by finding the number of permutations of these 9 moves, which is given by:
\[ \text{Number of paths} = \binom{9}{5} \]
Here, \(\binom{9}{5}\) denotes the binomial coefficient, which represents the number of ways to choose 5 moves (R) out of a total of 9 moves (R + U). This is the same as choosing 4 moves (U) out of 9, \(\binom{9}{4}\), due to the symmetry of combinations.
The formula for the binomial coefficient is:
\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
Applying this to the problem:
\[ \binom{9}{5} = \frac{9!}{5! \times 4!} = \frac{362880}{120 \times 24} = 126 \]
Therefore, there are 126 possible paths the ant can take from (0, 0) to (5, 4).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F19ccf01e-335f-4dab-a804-6828d515c4a4%2Fa05b2b87-a9a1-4542-a391-74bc25df75d3%2F1novdmj_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Problem 5:** An ant starts at the point (0, 0) and walks either one unit up, or one unit to the right, until it reaches the point (5, 4). How many possible paths can the ant take?
**Solution Explanation:**
To solve this problem, we can think of the ant's movement as a sequence of steps: the ant needs to make a total of 5 right moves and 4 up moves to reach the desired point. The order in which these moves are made determines the path.
The problem is equivalent to finding the number of ways to arrange a sequence of 5 "R" (right) moves and 4 "U" (up) moves. This is a combinatorial problem that can be solved using binomial coefficients.
The number of possible sequences can be calculated by finding the number of permutations of these 9 moves, which is given by:
\[ \text{Number of paths} = \binom{9}{5} \]
Here, \(\binom{9}{5}\) denotes the binomial coefficient, which represents the number of ways to choose 5 moves (R) out of a total of 9 moves (R + U). This is the same as choosing 4 moves (U) out of 9, \(\binom{9}{4}\), due to the symmetry of combinations.
The formula for the binomial coefficient is:
\[ \binom{n}{k} = \frac{n!}{k!(n-k)!} \]
Applying this to the problem:
\[ \binom{9}{5} = \frac{9!}{5! \times 4!} = \frac{362880}{120 \times 24} = 126 \]
Therefore, there are 126 possible paths the ant can take from (0, 0) to (5, 4).
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