An ant crawls on the floor along the curved path shown in the figure below. (Assume that the ant's initial motion is parallel to the y-axis and its final motion is parallel to the x-axis.) y (m) Vf = 0.190 m/s 0.350 V; = 0.190 m/s 0.150 t; · x (m) 0.100 0.390 The ant's positions and velocities are indicated for times t, = and t, = 5.40 s. Determine the x- and y-components of the ant's displacement, average velocity, and average acceleration between the two times. HINT (a) displacement (in m) Ax = Ay = (b) average velocity (in m/s) Vav, x m/s Vav, y m/s (c) average acceleration (in m/s?) |m/s² m/s? a av, x a av, y

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Chapter1: Units, Trigonometry. And Vectors
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An ant crawls on the floor along the curved path shown in the figure below. (Assume that the ant's initial motion is parallel to the y-axis and its final motion is parallel to the x-axis.)
у (m)
= 0.190 m/s
0.350
Jv; = 0.190 m/s
%3D
0.150
t;
х (m)
0.100
0.390
The ant's positions and velocities are indicated for times t; = 0 and te = 5.40 s. Determine the x- and y-components of the ant's displacement, average velocity, and average acceleration between the
two times.
HINT
(a) displacement (in m)
Ax =
m
Ду
m
(b) average velocity (in m/s)
V.
V, х
m/s
Vav, y
m/s
(c) average acceleration (in m/s2)
a av, x
m/s?
a av, y
m/s2
Transcribed Image Text:An ant crawls on the floor along the curved path shown in the figure below. (Assume that the ant's initial motion is parallel to the y-axis and its final motion is parallel to the x-axis.) у (m) = 0.190 m/s 0.350 Jv; = 0.190 m/s %3D 0.150 t; х (m) 0.100 0.390 The ant's positions and velocities are indicated for times t; = 0 and te = 5.40 s. Determine the x- and y-components of the ant's displacement, average velocity, and average acceleration between the two times. HINT (a) displacement (in m) Ax = m Ду m (b) average velocity (in m/s) V. V, х m/s Vav, y m/s (c) average acceleration (in m/s2) a av, x m/s? a av, y m/s2
Expert Solution
Step 1

Given:

Initial time, ti =0 s

Final time, tf = 5.40 s

 

Solution:

A. Displacement will be given as:

    x = 0.39 - 0.1 = 0.29 my =0.35 - 0.15 = 0.2 m

 

B. Average velocity will be given as:

   Vav,x = xt=0.295.4=0.0537 m/sVav,y = yt=0.205.4=0.0370 m/s

   

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