An annual championship event is the most widely watched sporting event in a country each year. In recent​ years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Complete parts​ (a) through​ (c).   Assuming that the population variances from the​ 30-second ads and the​ 60-second ads are​ equal, is there evidence of a difference in the mean score between the two types of​ ads? Use α=0.05.

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An annual championship event is the most widely watched sporting event in a country each year. In recent​ years, there has been a great deal of interest in the ads that appear during the game. These ads vary in length with most lasting 30 seconds or 60 seconds. The accompanying data represent the ad length and ad scores from a recent championship. Complete parts​ (a) through​ (c).
 
Assuming that the population variances from the​ 30-second ads and the​ 60-second ads are​ equal, is there evidence of a difference in the mean score between the two types of​ ads? Use
α=0.05.
 
Let μ1 be the mean score for the​ 30-second ads and μ2 be the mean score for the​ 60-second ads. Determine the hypotheses. Choose the correct answer below.
 
A. H0​: μ1≠μ2
     H1​: μ1=μ2
 
B. H0​: μ1=μ2
     H1​: μ1≠μ2
 
C. H0​: μ1≥μ2
     H1​: μ1<μ2
 
D. H0​:μ1≤μ2
     H1​: μ1>μ2
 
tSTAT=___
 
Choose the correct conclusion below.
___A___ H0. There is __B___ evidence that the mean scores differ.
 
A: Do not reject or reject
B: insufficient or sufficient 
 
p-value=____
 
Assuming that the population variances from both types of ads are​ equal, construct, and interpret a 95​% confidence interval estimate of the difference between the population means the score of the two types of ads.
 
The confidence interval is __ ≤μ1−μ2≤ __.
​(Type an integer or decimal rounded to two decimal places as​ needed.)
 
Interpret the confidence interval. Choose the correct answer below.
 
 
A. One can say with 95​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads falls in this interval.
 
B. One can say with 5​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads is smaller than the lower bound.
 
C. One can say with 5​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads is larger than the upper bound.
 
D. One can say with 95​% confidence that the difference between the population mean score of the​ 30-second ads and the​ 60-second ads falls outside this interval.
Instructor-created question
An annual championship event is the most widely watched
seconds or 60 seconds. The accompanying data represent
30-Second Ads 60-Second Ads
47 20 31 30 47 62 57 52 55 50
46 21 35 54 53 29 30 36 42 65
a. Assuming that the population variances from the 30-secol
Let H1
be the mean score for the 30-second ads and u2 be t
OA. Ho: H1 #H2
H:H1=H2
OC. Ho: H1Z H2
Transcribed Image Text:Instructor-created question An annual championship event is the most widely watched seconds or 60 seconds. The accompanying data represent 30-Second Ads 60-Second Ads 47 20 31 30 47 62 57 52 55 50 46 21 35 54 53 29 30 36 42 65 a. Assuming that the population variances from the 30-secol Let H1 be the mean score for the 30-second ads and u2 be t OA. Ho: H1 #H2 H:H1=H2 OC. Ho: H1Z H2
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