an angle of 20.0° above the horizontal and at a speed of 11.0
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- A skier is travelling horizontally across frictionless snow at 10 m/s. He goes up an also frictionless slope and his speed drops to 5 m/s at the top when he resumed moving horizontally. How high did he go?Two position vectors are given by Á = (4.00m)î – (2.00m)j – (3.00m)k and B= (4.00m)i - (5.00m)k. What is the scalar product of (3Á) · B? O (16.0m²)î + (15.0m²)k O 31 m2 (48.0m2)i + (45.0m2)k O 93 m2 O None of the above.How much gravitational potential energy (in J) (relative to the ground on which it is built) is stored in an Egyptian pyramid, given its mass is about 6 ✕ 109 kg and its center of mass is 26.0 m above the surrounding ground? What is the ratio of this energy to the daily food intake of a person (1.2 ✕ 107 J)?
- A block is placed on a frictionless ramp at a height h; of 14.5 m above the ground. Starting from rest, the block slides down the ramp. At the bottom of the ramp, the block slides onto a frictionless horizontal track without slowing down. At the end of the horizontal track, the block slides smoothly onto a second frictionless ramp. 01 = 43.3° 02 = 19.5° How far along the second ramp does the block travel before coming to a momentary stop, as measured along the incline of the ramp? distance traveled along second ramp: m After the block comes to a complete stop on the second ramp, it will then begin moving back down the second ramp. What is the speed of the block when it is 9.25 m, vertically, above the ground? speed of the block: m/s(a) How much gravitational potential energy (relative to the ground on which it is built) is stored in an Egyptian pyramid, given its mass is about 6 ✕ 109 kg and its center of mass is 30.0 m above the surrounding ground? J(b) What is the ratio of this energy to the daily food intake of a person (1.2 ✕ 107 J)?For two position vectors, A = -4.00i +2.00j -3k, B = 4.00i - 6.00j What is the scalar (dot) product (2A) (3B)?