An analytical chemist is titrating 168.4 ml. of a 0.7600M solution of aniline (C,H,NH,) with a 0.8100M solution of HIO,. The p K, of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 167.3 ml. of the HIO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO, solution added. Round your answer to 2 decimal places.

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Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
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An analytical chemist is titrating 168.4 mL of a 0.7600M solution of aniline (C,H,NH,) with a 0.8100M solution of HIO,. The p K, of
aniline is 9.37. Calculate the pH of the base solution after the chemist has added 167.3 mL of the HIO, solution to it.
Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO, solution
added.
Round your answer to 2 decimal places.
pH = 0
%3!
Transcribed Image Text:An analytical chemist is titrating 168.4 mL of a 0.7600M solution of aniline (C,H,NH,) with a 0.8100M solution of HIO,. The p K, of aniline is 9.37. Calculate the pH of the base solution after the chemist has added 167.3 mL of the HIO, solution to it. Note for advanced students: you may assume the final volume equals the initial volume of the solution plus the volume of HIO, solution added. Round your answer to 2 decimal places. pH = 0 %3!
A chemist titrates 250.0 ml of a 0.6655M sodium hydroxide (NAOH) solution with 0.3489M HNO, solution at 25 °C. Calculate the pH at
equivalence.
Round your answer to 2 decimal places.
Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO, solution
added.
DH - 0
Transcribed Image Text:A chemist titrates 250.0 ml of a 0.6655M sodium hydroxide (NAOH) solution with 0.3489M HNO, solution at 25 °C. Calculate the pH at equivalence. Round your answer to 2 decimal places. Note for advanced students: you may assume the total volume of the solution equals the initial volume plus the volume of HNO, solution added. DH - 0
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