An amount of 11 pennies is distributed randomly to 6 persons (the order is important here, i.e., (1,2,3,2,2,1) is going to be different than (1,3,2,2,2,1)). What is the probability that at least four of them get an equal amount? 11/312 51/1456 7/208 53/1456 6/91

A First Course in Probability (10th Edition)
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Chapter1: Combinatorial Analysis
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Problem 1.1P: a. How many different 7-place license plates are possible if the first 2 places are for letters and...
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An amount of 11 pennies is distributed randomly to 6 persons (the order is
important here, i.e., (1,2,3,2,2,1) is going to be different than (1,3,2,2,2,1)). What is
the probability that at least four of them get an equal amount?
11/312
51/1456
7/208
53/1456
O 6/91
Transcribed Image Text:An amount of 11 pennies is distributed randomly to 6 persons (the order is important here, i.e., (1,2,3,2,2,1) is going to be different than (1,3,2,2,2,1)). What is the probability that at least four of them get an equal amount? 11/312 51/1456 7/208 53/1456 O 6/91
How many terms we have in the sum
13
a²b³c*dm
i, j, k, m
i+j+k+m=13
with
i, j, k, m non-negative integers?
1820
560
1365
455
1001
Transcribed Image Text:How many terms we have in the sum 13 a²b³c*dm i, j, k, m i+j+k+m=13 with i, j, k, m non-negative integers? 1820 560 1365 455 1001
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