**Transcription for Educational Website****Problem Statement:**An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.215 V/m imposed along its entire length. The temperature of the wire is 45.0°C. Assume one free electron per atom.**Questions:**(a) Use the information in this Table of Resistivities and Temperature Coefficients to determine the resistivity (in Ω · m) of aluminum at this temperature. \(\rho = \_\_\_\_\_\) Ω · m(b) What is the current density (in MA/m²) in the wire? \(J = \_\_\_\_\_\) MA/m²(c) What is the total current (in mA) in the wire? \(I = \_\_\_\_\_\) mA(d) What is the drift speed of the conduction electrons? \(v_d = \_\_\_\_\_\) μm/s(e) What potential difference must exist between the ends of a 2.50 m length of the wire to produce the stated electric field? \(\Delta V = \_\_\_\_\_\) V**Explanation of Diagrams and Graphs:**There are no graphs or diagrams included in the provided content.

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An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.215 V/m imposed along its entire length. The temperature of the wire is 45.0°C. Assume one free electron per atom. (a) Use the information in this Table of Resistivities and Temperature Coefficients to determine the resistivity (in 2 m) of aluminum at this temperature. Ω· m p= (b) What is the current density (in MA/m²) in the wire? J = MA/m² (c) What is the total current (in mA) in the wire? I = mA

An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.215 V/m imposed along its entire length. The temperature of the wire is 45.0°C. Assume one free electron per atom. (a) Use the information in this Table of Resistivities and Temperature Coefficients to determine the resistivity (in 2 m) of aluminum at this temperature. Ω· m p= (b) What is the current density (in MA/m²) in the wire? J = MA/m² (c) What is the total current (in mA) in the wire? I = mA

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Concept explainers

Microscopic view of current

In physics, the term current is expressed as the rate of flow of electric charges across the area per unit time (I=q/t). It propagates along in the direction of the motion of positive charges. When the current is caused by the motion of electrons, the direction of the current is opposite to the flow.

Question

**Transcription for Educational Website**

**Problem Statement:**

An aluminum wire with a diameter of 0.115 mm has a uniform electric field of 0.215 V/m imposed along its entire length. The temperature of the wire is 45.0°C. Assume one free electron per atom.

**Questions:**

(a) Use the information in this Table of Resistivities and Temperature Coefficients to determine the resistivity (in Ω · m) of aluminum at this temperature.

\(\rho = \_\_\_\_\_\) Ω · m

(b) What is the current density (in MA/m²) in the wire?

\(J = \_\_\_\_\_\) MA/m²

(c) What is the total current (in mA) in the wire?

\(I = \_\_\_\_\_\) mA

(d) What is the drift speed of the conduction electrons?

\(v_d = \_\_\_\_\_\) μm/s

(e) What potential difference must exist between the ends of a 2.50 m length of the wire to produce the stated electric field?

\(\Delta V = \_\_\_\_\_\) V

**Explanation of Diagrams and Graphs:**

There are no graphs or diagrams included in the provided content.

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